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Vlad1618 [11]
4 years ago
8

Why do electrons enter the 4s orbital before entering the 3d orbital?

Chemistry
1 answer:
Alla [95]4 years ago
3 0
<span>because  the 4s orbitals have a lower energy than the 3d, and so the 4s orbitals are filled first.</span>
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What is the area under the curve for the histogram below?
kodGreya [7K]

Answer:

Explanation:

There is no histogram

3 0
3 years ago
Read 2 more answers
Suppose a compound is involved in three different reactions denoted R1, R2, and R3. Tripling the concentration of this reactant
pickupchik [31]

Answer:

The order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

Explanation:

The rate of a chemical reaction is the number of moles of reactants consumed per unit time or the number of moles of products formed per unit. the rate of a chemical reaction is affected by the concentration of reactants

The relationship between the rate of a chemical reaction and the concentration of its reactants is given by the rate law or equation.

Generally, the rate equation is given as;

Rate = k[A]ᵃ[B]ᵇ..., where k = rate constant which is independent of concentration of the reactants, [A] = concentration of reactant A, a = order of reaction A, [B] = concentration of reaction B, b = order of reaction B.

For the given reactions R1, R2 and R3

For R1; rate = 3, Concentration = 3[A]

3 = k[A]3ˣ

3¹ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 1

For R2; rate = 9, Concentration = 3[A]

9 = k[A]3ˣ

3² = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 2

For R1; rate = 1, Concentration = 3[A]

1 = k[A]3ˣ

3⁰ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 0

Therefore, the order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

6 0
3 years ago
Find the empirical formula of the following compounds:<br> (c) A hydrocarbon with 79.9 mass % carbon
rodikova [14]

The compound is 82.76% C and 17.24% H

In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.

<h3>Describe the empirical formula.</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea.

The simplest whole number ratio of each type of atom in a compound is its empirical formula. It can be determined from data on the mass of each component in a compound or from the composition's proportion.

To learn more about chemical reaction visit:

brainly.com/question/14044066

#SPJ4

8 0
2 years ago
Feeding levels within an ecosystem are
alisha [4.7K]

Answer:

C. trophic levels

Explanation:

Trophic levels are the feeding positions of all organisms in a specific ecosystem. There are five main trophic levels, or feeding levels.

-----------

Habitats are the environment in which organisms live. They are not feeding levels.

Taxonomic levels are a way of classifying species. They consist of (in order) domain, kingdom, phylum, class, order, family, genus, and species. They are not feeding levels.

Cladograms are branching diagrams that show the relationship between multiplt organisms/species. It too is not a feeding level.

Thus, is answer is C.

hope this helps!

3 0
2 years ago
The value of the equilibrium constant for the following chemical equation is Kr 40 at 25°C. Calculate the solubility of Al(OH)s(
dedylja [7]

Answer:

0,040 M

Explanation:

The global reaction of the problem is:

Al(OH) (s) + OH⁻ ⇄ Al(OH)₂⁻(aq) K= 40

The equation of equilibrium is:

K = \frac{[Al(OH)_{2} ^-]}{[Al(OH)][OH^-]}

The concentration of OH⁻ is:

pOH = 14 - pH = <em>3</em>

pOH = -log [OH⁻]

[OH⁻] = 1x10⁻³

Thus:

40 = \frac{[Al(OH)_{2} ^-]}{[Al(OH)][1x10^{-3}]}

<em>0,04M =  \frac{[Al(OH)_{2} ^-]}{[Al(OH)]}</em>

This means that 0,04 M are the number of moles that the solvent can dissolve in 1L, in other words, solubility.

I hope it helps!

7 0
3 years ago
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