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raketka [301]
1 year ago
11

Lea and Rob are selling fruit for a school fundraiser. Customers can buy small boxes of orangesand large boxes of oranges. Lea s

old 2 small boxes of oranges and 1 large box of oranges for atotal of $12. Rob sold 3 small boxes of oranges and 1 large box of oranges for a total of $16.Find the cost each of one small box of oranges and one large box of oranges.
Mathematics
1 answer:
MaRussiya [10]1 year ago
7 0

The first step is to define the system of equations.

Take x and y as the cost of a small box and a large box respectively.

\begin{gathered} 2x+y=12 \\ 3x+y=16 \end{gathered}

Solve the system.

\begin{gathered} 2x+y=12 \\ y=12-2x \\ 3x+y=16 \\ y=16-3x \end{gathered}\begin{gathered} 12-2x=16-3x \\ 3x-2x=16-12 \\ x=4 \end{gathered}\begin{gathered} y=12-2x \\ y=12-2\cdot4 \\ y=12-8 \\ y=4 \end{gathered}

A small box costs $4 and a large box costs $4 too.

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Cylinder has a height of 15 centimeters and a radius of 10 centimeters. What is its volume? Use ​ ≈ 3.14 and round your answer t
tatuchka [14]

Answer: 4712.39 centimeters

Step-by-step explanation: Using the volume of a cylinder calculator, I got the answer of 4712.3889803847 centimeters, but rounded it to the nearest hundreth. Hope this helps!

3 0
3 years ago
Cosx+1/sin^3x=cscx/1-cosx
ANTONII [103]
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

 </span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).

 </span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.

 </span>
<span>I hope this helps! </span>
8 0
3 years ago
Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side
svp [43]
A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
      = (7 - 5) ÷ 2
      = 2 ÷ 2
      = 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²) 
      = √(5² - 1²)
      = √(25 - 1)
      = √24
      = 2√6

Last, we have all the information needed in order to calculate the area by the formula:

A =  \frac{(AB + CD)DH}{2}

A = (7 + 5) × 2√6 ÷ 2
   = 12√6

The area of the regular trapezoid is 12√6 square units.

7 0
3 years ago
Find the measure of the third angle of a triangle given the measures of two angles.<br> 34 and 88
romanna [79]

Answer:

58

Step-by-step explanation:

All three angles of a triangle have to add up to 180. Given this we can do the following problem:

180-34-88 = 58

3 0
3 years ago
The profits of mr cash’s company is represented by the equation p(t)=-3t^2+18t-4, where p(t) is the amount of profit in hundreds
eduard
We have that

<span>p(t)=-3t^2+18t-4

using a graphing tool, we can see the maximum of the graph
(see the attached figure)

A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?

</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)

<span>B) What is the maximum profit? 

23 (hundred of thousand of dollars) = 2.300.000 dollars

</span>c) What time will it be two late?
 
(This is the time when the graph crosses zero and the profits turn into losses )

5.77 years, or an estimate of about  69 months.

4 0
3 years ago
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