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mihalych1998 [28]
3 years ago
13

Use the distributive property to remove the parentheses. 9(x-5)

Mathematics
1 answer:
anygoal [31]3 years ago
8 0
Is this what you're looking for?

<span>=<span><span>(9)</span><span>(<span>x+<span>−5</span></span>)</span></span></span><span>=
<span><span><span>(9)</span><span>(x)</span></span>+<span><span>(9)</span><span>(<span>−5</span>)</span></span></span></span><span>=
<span><span>9x</span>−<span>45</span></span></span>
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Solve the equation using the quadratic formula. Enter each solution in simplest form.
sergeinik [125]

For this case we have the following quadratic equation:

x ^ 2-4x + 23 = 0

The solutions will be given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

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a = 1\\b = -4\\c = 23

Substituting the values we have:

x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}

We have two roots:

x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}

ANswer:

x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}

6 0
4 years ago
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