$\left[\begin{array}{ccc}-1&3\\5&4\end{array}\right] \cdot \left[\begin{array}{ccc}0&-2&6\\1&-3&2\end{array}\right]\\\\= \left[\begin{array}{ccc}(-1)(0)+(3)(1)&(-1)(-2)+(3)(-3)&(-1)(6)+(3)(2)\\(5)(0)+(4)(1)&(5)(-2)+(4)(-3)&(5)(6)+(4)(2)\end{array}\right]\\\\= \left[\begin{array}{ccc}0+3&2-9&-6+6\\0+4&-10-12&30+8\end{array}\right]\\\\ =\left[\begin{array}{ccc}3&-7&0\\4&-22&38\end{array}\right]$

3 0

3 years ago

Answer choices: (5,6) (5,2) (3,6) (3,2).

Degger [83]

Answer:

(3,6)

Step-by-step explanation:

If the starting point is the dot then we start from there - (4,4) then we go up 2 units at (4,6) then moving one unit to the left our answer is (3,6).

6 0

3 years ago

Question in picture

lara [203]

You need to create a chart like the one attached and put your own values in it. The teacher wants atleast 3 inputs and outputs but 4 or 5 is better. You first need to create a rule (EX: x+1=y)

8 0

3 years ago

Please help ASAP, giving brainliest!

scoundrel [369]

Answer:no

Step-by-step explanation:

Because you have two -2 in the x slots , if you see an number more than once it is no longer a function.

7 0

3 years ago