All categories

4 years ago

Adolfo spends $48 on school supplies.The sales tax is 7%.What is the total cost of the supplies?

Mathematics

1 answer:

Ganezh [65]4 years ago

7 0

The answer would be $51.36

48.00 x 7% = 3.36

48.00 + 3.36 = $51.36

You might be interested in

Given A(-3,6) and B(5,-6) find the distance and midpoint between each

xenn [34]

14.42 is your distance formula
(1,0) is the midpoint
if you need the forma for distance it is x2-x1 squared + y2-y1 squared then square root it

7 0

4 years ago

Read 2 more answers

Find the value of x and the value of y.

tensa zangetsu [6.8K]

Answer:bro want to be friends i have none

Step-by-step explanation:

5 0

3 years ago

Doogle drove 30 and one-third miles toward his brother's house in one-third of an hour. About how long will the entire 100-mile

Olenka [21]

Answer:

$1\frac{9}{91}\ hours$

Step-by-step explanation:

we know that

30 and one-third miles is equal to

$30\frac{1}{3}\ mi=\frac{30*3+1}{3}=\frac{91}{3}\ mi$

one-third of an hour is equal to

$\frac{1}{3}\ h$

Applying proportion

$\frac{(1/3)}{(91/3)}\frac{h}{mi}=\frac{x}{100}\frac{h}{mi}\\ \\x=\frac{100}{91}\ h$

Convert to mixed number

$\frac{100}{91}\ h=\frac{91}{91}+\frac{9}{91}=1\frac{9}{91}\ h$

8 0

4 years ago

Read 2 more answers

What do I do for this one

PIT_PIT [208]

Answer:

substitute x=1/2 in the equation then it will be

$8 + 2( \frac{ 1}{2} ) \\ = 9$

3 0

4 years ago

Read 2 more answers

If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.

alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

So, no option is correct. And the answer is

$T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

Learn more about linear transformations here-

brainly.com/question/13005179

#SPJ10

5 0

2 years ago