The solution to the above question is -147
-3[(w-6) ^2+x] ^2 where the value of w = 5 and x amounts to 6
Using algebraic identity: (a-b) ^2 = (a^2 -2ab+b^2)
= -3 [(w^2 -2w*6 +6^2) + x] ^2
= -3 [(w^2 -12w+36) + x] ^2
now substitute the value of w = 5
= -3 [(5^2 -12*5+36) + x] ^2
= -3 [(25 -60+36) + x] ^2
= -3 [1+ x] ^2
Using algebraic identity: (a+ b) ^2 = a^2 +2ab + b^2
= -3 [1^2+2x*1+ x^2]
= -3 [1+2x+ x^2]
now substitute the value of x = 6
= -3 [1+2*6+ 6^2]
= -3 [1+12+ 36]
= -3 [49]
= -147
The above answer can be derived through direct substitution also. Both the methods will any way give the same answer.
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