For this problem, the confidence interval is the one we are looking
for. Since the confidence level is not given, we assume that it is 95%.
The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n
Where:
<span>
</span>
α= 5%
α/2
= 2.5%
t
0.025, 19 = 2.093 (check t table)
n
= 20
df
= n – 1 = 20 – 1 = 19
So plugging in our values:
8.41 ± 2.093 * 0.77 √ 1 + 1/20
= 8.41 ± 2.093 * 0.77 (1.0247)
= 8.41 ± 2.093 * 0.789019
= 8.41 ± 1.65141676
<span>= 6.7586 < x < 10.0614</span>
<h3>Key points :-</h3>
᪥ The formula to find the 31st term is : 
᪥ In the formula, 
represents the first term of the sequence.
᪥ 
is the number of terms, In our case n is 31.
᪥ 
is the common difference between the terms, In our case d is 4.
<em>Detailed Solution is attached</em>᭄
Answer:
It falls between √7 and √8
Step-by-step explanation:
Please kindly check the attached file for explanation.
