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MrMuchimi
1 year ago
14

Lennard-jones potential diagrams, also called intermolecular potential energy diagrams, illustrate the relationship between the

potential energy of a molecule as the distance between the two nuclei changes.
Select all of the true statements regarding Lennard-Jones potential diagrams.

Chemistry
1 answer:
amm18121 year ago
7 0

Statement 3, 5 and 6 are true statements regarding Lennard-Jones potential diagrams

What is lennard- jones potential diagrams

  • It describes potential energy of interaction between two non-bonding atoms or molecules based on their distance of separation.
  • It illustrates the relationship between potential energy of a molecule as the distance between the two nuclei changes.

Statement 3 ,5 and 6 are correct statements

  • When attractive forces are greater than repulsive forces, the two nuclei will continue to come closer.
  • When attractive forces are smaller than repulsive forces, the two nuclei will continue to go farther.
  • Once a balance is found between attractive and repulsive forces, an equilibrium distance called bond length is achieved.

Learn more about lennard- jones potential diagrams at brainly.com/question/13348153

#SPJ13

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A horizontal cylinder equipped with a frictionless piston contains 785 cm3 of steam at 400 K and 125 kPa pressure. A total of 83
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Answer:

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d. 64.5J

Explanation:

From the question, we can identify the following;

V_{o} = 785cm^{3} = 0.000785 m^{3}

T_{o} = 400K

P_{o} = 125 Kpa =  125 000 Pa

Using the ideal gas equation,

PV = nRT

where R is the molar gas constant = 8.314 m^{3}⋅Pa⋅K^{-1}⋅mol^{-1}

Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

a. Steam temperature in K

To calculate this, we use the constant pressure process;

q = nΔH

Where q is 83.8J according to the question

Thus;

83.8 = 0.03 × [34980 + 35.5T_{1} - (34980 + 35.5T_{o})]

83.8 = (0.03 × 35.5) (T_{1} - 400K)

83.8 = 1.065 (T_{1}  - 400)

78.69 = (T_{1}  - 400)

T_{1} = 400 + 78.69

T_{1}  = 478.69 K

b. Final cylinder volume

To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

V_{1}/T_{1} = V_{o}/T_{o}

V_{1}  =  V_{o}T_{1}/T_{o}

V_{1}   = (785 × 478.69)/400

V_{1}   = 939.43 cm^{3}

c. Work done by the system

Mathematically, the work done by the system is calculated as follows;

w = P(V_{1}- V_{o}) = 125 KPa ( 939.43 - 785) = 19.30 J

d. Change in internal energy of the steam in J

ΔU = q - w = 83.8 - 19.3 = 64.5J

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A

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