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attashe74 [19]
3 years ago
7

Why does mass decrease when sugar dissolved in water

Chemistry
1 answer:
kap26 [50]3 years ago
7 0

Answer:

Because the same amount of sugar is still there. The solid sugar crystals break apart in water as the sugar dissolves, but the individual sugar particles or molecules are still present and do not change as a result of dissolving in the water. The combined mass of the sugar and water shouldn't change.

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What is the molarity of 2 moles of iron oxide,FeO in 8 Liters of water
faust18 [17]

Answer : 0.25 M

explanation :

- Molarity is the number of moles of solute per liters of solvent.

- Molarity (M) = (n) / V (liter) = 2 / 8 = 0.25 M


5 0
2 years ago
Copper has a density of 8.920 g/cm3. What mass of copper will occupy 45cm3? What volume of copper will have a mass of 1.0 kg?
mixas84 [53]
Density = mass/volume
so rearranged mass = volume x density
mass = 8.920 x 45 = 401.4g

rearrange   (there are 1000grams in 1kg)
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5 0
3 years ago
Consider the unbalanced equation for the oxidation of aluminum.
SashulF [63]
In order to balance an equation, we apply the principle of conservation of mass, which states that mass can neither be created nor destroyed. Therefore, the mass of an element before and after a reaction remains constant. Here, the balanced equation becomes:
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8 0
2 years ago
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For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

S_2=0.002 M

Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

Initial concentration of

H_2S=0.30M

H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles  of reactant reduced and form product

Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

Now, equilibrium concentration  of gases

H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

3 0
2 years ago
What is transferred by all types of waves? A. electrons B. energy C. heat D. matter
saveliy_v [14]
<span>B. energy
hope it helps
</span>
6 0
3 years ago
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