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Shtirlitz [24]
3 years ago
8

E

Chemistry
2 answers:
Nana76 [90]3 years ago
7 0
Hey :)

Air pollution

Hope this helps!

Good luck in your test :)
Schach [20]3 years ago
3 0
It is E because are water land underground and more
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Pyruvate is the end product of glycolysis. Its further metabolism depends on the organism and on the presence or absence of oxyg
murzikaleks [220]

The given question is incomplete. The image present in the question for Reaction A is attached below along with the answer.

Explanation:

Pyruvate molecule reacts with Coenzyme A in the presence of oxygen and it results in the formation of acetyl Coenzyme A and carbon dioxide.

The enzyme pyruvae dehydrogenase helps in catalyzing this reaction. As in this biochemical reaction NAD^{+} gets converted into NADH.

This reaction is shown in the image attached below.  

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3 years ago
The volume occupied by 12.5 moles of nitrogen gas at STP is liters.​
Naddik [55]

Answer:

There is no picture, how can we help?

Explanation:

4 0
2 years ago
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The acid-dissociation constants of HC3H5O3 and CH3NH3+ are given in the table below. Which of the following mixtures is a buffer
sergey [27]

Answer:

A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH

Explanation:

The pH of a buffer solution is calculated using following relation

pH=pKa+log(\frac{salt}{acid} )

Thus the pH of buffer solution will be near to the pKa of the acid used in making the buffer solution.

The pKa value of HC₃H₅O₃ acid is more closer to required pH = 4 than CH₃NH₃⁺ acid.

pKa = -log [Ka]

For HC₃H₅O₃

pKa = 3.1

For CH₃NH₃⁺

pKa = 10.64

pKb = 14-10.64 = 3.36 [Thus the pKb of this acid is also near to required pH value)

A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH

Half of the acid will get neutralized by the given base and thus will result in equal concentration of both the weak acid and the salt making the pH just equal to the pKa value.

8 0
2 years ago
What type of reaction is the decay of carbon-14
ivolga24 [154]
First order reaction ?

3 0
3 years ago
A sample of an unknown compound is vaporized at 180.°C. The gas produced has a volume of 2010.mL at a pressure of 1.00atm, and i
stiv31 [10]

<u>Answer:</u> The molar mass of the given unknown compound is 50.5 g/mol.

<u>Explanation:</u>

To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of sample = 1.00 atm

V = volume of sample = 2010 mL = 2.010 L   (Conversion factor: 1 L = 1000 mL)

m = Given mass of unknown compound = 2.73 g

M = Molar mass of unknown compound = ? g/mol

R = Gas constant = 0.0820\text{ L atm }mol^{-1}K^{-1}

T = temperature of sample = 180^oC=[180+273]K=453K

Putting values in above equation, we get:

1.00atm\times 2.010L=\frac{2.73g}{M}\times 0.0820\text{ L atm }mol^{-1}K^{-1}\times 453K\\\\V=50.45g/mol

Rounding off to 3 significant figures, we get the molar mass to be 50.5 g/mol.

Hence, the molar mass of the given unknown compound is 50.5 g/mol.

8 0
3 years ago
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