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2 years ago

Why do solids have a fixed shape?

Chemistry

2 answers:

KIM [24]2 years ago

5 0

D. The particles are tightly packed together

il63 [147K]2 years ago

3 0

Answer:

Explanation:

I took the test

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What is water clarity and why is it important?

il63 [147K]

Answer:

it's a measure of how far down light can penetrate through the water column. ... Because water clarity is closely related to light penetration, it has important implications for the diversity and productivity of aquatic life that a system can support

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2 years ago

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The isomerization of methylisonitrile to acetonitrile (CH3NC(g) ???? CH3CN) is first order in CH3NC. The rate constant for the r

Hoochie [10]

Answer:

The half life is $H_{1/2}= 7333.3sec$

Explanation:

The half life of a first order reaction is mathematically represented as

$H_{1/2} = \frac{0.693}{Rate Constant }$

Substituting $9.45 * 10^{-5}s^{-1}$ for the rate constant

$H_{1/2} = \frac{0.693}{9.45*10^{-5}}$

$H_{1/2}= 7333.3sec$

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2 years ago

Which kind of energy does an object have because of its height above Earth's

jonny [76]

Answer:

C po

Explanation:

baka po pero pwd din ang B pero ok ang C

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2 years ago

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How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you

SOVA2 [1]

Explanation:

The given data is as follows.

Concentration of solution = 0.5 M

Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically, Molarity = $\frac{\text{No. of moles}}{\text{Volume}}$

Hence, calculate the number of moles as follows.

No. of moles = Molarity × Volume

= $0.5 M \times 1 L$

= 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

= $0.5 mol \times 132.119 g/mol$

= 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.

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3 years ago

Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a

GrogVix [38]

Answer:

The calorie content of 65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium) + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41 * (65/15) = 326.78 cal

8 0

2 years ago