All categories

1 year ago

What number is in the hundreds place after

Mathematics

1 answer:

Vika [28.1K]1 year ago

6 0

The digit in the hundreds place is 4

From the question, we have

(21 × 10¹)+(3×10²) + (9 × 10²)

=210+300+900

=1410

The digit in the hundreds place is 4 and the value is 400.

Multiplication:

Mathematicians use multiplication to calculate the product of two or more numbers. It is a fundamental operation in mathematics that is frequently utilized in everyday life. When we need to combine groups of similar sizes, we utilize multiplication. The fundamental concept of repeatedly adding the same number is represented by the process of multiplication. The results of multiplying two or more numbers are known as the product of those numbers, and the factors that are multiplied are referred to as the factors. Repeated addition of the same number is made easier by multiplying the numbers.

To learn more about multiplication visit: brainly.com/question/5992872

#SPJ1

You might be interested in

Worth 50 Points!!

Naddika [18.5K]

Hello There!

These statements are not equal. If you solve them, you will not get the same value.

Hope This Helps You!
Good Luck :)

7 0

2 years ago

Which inequality is true? ОА. 2. — 1<5 ОВ. 3л > 9 ос. п+8 < 11 OD. 5 > 2

matrenka [14]

N is the answer to this question

6 0

2 years ago

Find the remainder when f(x) = 2x3 − 12x2 + 11x + 2 is divided by x − 5.

Likurg_2 [28]

Answer: I couldn’t find your answer to this mathematics question, try a different question to this mathematics answer so I can get it.

Step-by-step explanation:

6 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

vfiekz [6]

For AD:
AD=root((c-0)^2 + (d-0)^2)=root((c)^2 + (d)^2)
For BC:
BC=root(((b+c) - b)^2+(d-0)^2)=root((c)^2+(d)^2)
For AB:
AB=root((b-0)^2 + (0-0)^2)=root((b)^2 + (0)^2)=root((b)^2)
For CD:
CD=root((c-(b+c))^2 + (d-d)^2)
CD=root((b)^2 + (0)^2)
CD=root((b)^2)

8 0

3 years ago

What is the answer and how do you solve 21x^3/3x^−1

Sunny_sXe [5.5K]

Answer:

as written: 7x^2

perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

$\dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2$

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

21x^3/(3x^-1)

then the simplification is ...

$\dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4$

_____

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^b/a^c = a^(b-c)

6 0

3 years ago