The profit is maximized when approximately 517 units is produced.
<h3>What is a profit function?</h3>
A profit function is the difference between revenue and cost.
The given cost function is presented as follows;
C(x) = 1200 + 500•x - 2.6•x² + 0.04•x³
The demand function is presented as follows;
p(x) = 1700 - 8•x
Required;
The production level that will maximize profitm.
Solution;
From the demand function, we have;
The price = x
Therefore;
Revenue, R(x) = x × (1700 - 8•x) = 1700•x - 8•x²
Therefore;
Profit = R(x) - C(x)
Which gives;
Profit = 1700•x - 8•x² - (1200 + 500•x - 2.6•x² + 0.04•x³) = -0.04•x³+5.4•x²-750•x+750
At maximum profit, we have;
- Profit' = -3•x²-135.2•x +3000 = 0
Which gives;
x ≈ 64.66
Therefore;
The quantity that gives the most profit is as follows;
P(x) ≈ 1700 - 64.66×8 ≈ 517.28
The production level that will maximize profit is therefore approximately 517 units
Learn more about the profit function here:
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