Question

At one university, the mean distance commuted to campus by students is 19.0 miles, with a standard deviation of 4.2 miles. Suppose that the commute distances are normally distributed. Complete the following statements. (a) Approximately 95% of the students have commute distances between miles and miles. (b) Approximately 7 miles and 31.6 miles. of the students have commute distances between 6.4

Answer 1

The average commute for 95% of the students is between 19.0 and 4.2 miles.

The average distance is 19 miles.

Therefore, the standard deviation is 4.2 miles.

A) 2.7 = 19 - a(4.2)

where;

a deviates from the mean by a certain number of standard deviations. Thus;

a = (19 - 2.7) ÷ 4.2

a = 3

In a normal distribution, 3 standard deviations from the mean indicate that 95% of the data falls within that range.

B) The data are 2 standard deviations apart from the mean at the 95% confidence level. Thus;

CI = 19 ± 2(4.2)

CI = (18 - 10.2) OR (18 + 10.2)

CI = (7.8, 28.2)

Learn more about confidence intervals at

brainly.com/question/17097944

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