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jolli1 [7]
3 years ago
9

Are these equations infinite solution, no solution, or one solution?

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

1) one solution

2) Infinitely many solution

3) no solution

Step-by-step explanation:

The first equation is -14-8x=-2(-3x+7)

Let us expand the right hand side to get:

-14-8x=-2*-3x+-2*7

We multiply -14-8x=6x-14

We group similar terms to get:

-8x-6x=-14+14

Combine similar terms to get:

-14x=0

Divide through by -14 to get:

x=0

2) The second equation is 3+5x=5(x+2)-7

We expand to obtain:

3+5x=5x+5*2-7

Multiply to get:

3+5x=5x+10-7

This gives us

3+5x=5x+3

5x=5x

1=1

There is infinitely many solutions

3) The third equation is: 36-7x=-7(x-5)

We expand to get:

36-7x=-7x+35

Group similar terms;

-7x+7x=35-36

0=-1

This statement is not true so there is no solution.

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Step-by-step explanation:

look at the first number in each set then find the smallest and the biggest that is how you find range

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7 0
2 years ago
A carpenter bought 750 nails. Each nail has a mass of 5.2×10−3 kilogram. What is the total mass, in kilograms, of the nails the
lawyer [7]

The total mass, in kilograms, of the nails the carpenter bought is 3.9 kilogram

<h3><u>Solution:</u></h3>

Given that carpenter bought 750 nails

Each nail has a mass of 5.2 \times 10^{-3} kilogram

To find: total mass, in kilograms of the nails bought

The total mass of the nails bought can be found out by multiplying number of nails bought by mass of each nail

Number of nails bought = 750

Mass of each nail = 5.2 \times 10^{-3} kilogram

total mass of the nails bought = number of nails bought x mass of each nail

\text {total mass of the nails bought }=750 \times 5.2 \times 10^{-3}

\text {total mass of the nails bought }=3900 \times 10^{-3}=\frac{3900}{1000}=3.9

Thus the total mass of nails bought is 3.9 kilogram

4 0
3 years ago
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