The cost of maintaining car A is $300 per year plus $.014 per mile driven. The cost of maintaining car B is $200 per year plus $
.025 per mile driven. How many miles are driven in the first year in order for the total costs between car A and B to be equal?Car A = 300+.014xCar B =200+.025xSolve the following equation to determine when costs are equal300+.014x=200+.025x.011x=100
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The answer would be the first choice.
Explanation: The reason for this is that the question was pretty much just asking what the area of the resulting two-dimensional cross section would be -the shape in gray- (which can be found by using the formula . To add on, since the dimensions of the shape are already given (5 and 3) all you've to do is multiply: 3*5=15
That's how you get to the answer.