Question

The cost of maintaining car A is $300 per year plus $.014 per mile driven. The cost of maintaining car B is $200 per year plus $.025 per mile driven. How many miles are driven in the first year in order for the total costs between car A and B to be equal?Car A = 300+.014xCar B =200+.025xSolve the following equation to determine when costs are equal300+.014x=200+.025x.011x=100

Answer 1

When cost is equal

$\begin{gathered} 300+0.14x=200+0.025x \\ 300-200=0.25x-0.014x \\ 100=0.011x \\ x=\frac{100}{0.011} \\ x=9090.90909091 \\ x=9090.91 \end{gathered}$