Answer :Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.
Step-by-step explanation:
Considering the quadrilateral with vertices
d(0,0)
i(5,5)
n(8,4)
g(7,1)
Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.
From the figure a, it is clear that the quadrilateral has
Two pairs of sides
Each pair having two equal-length sides which are adjacent
The angles being equal where the two pairs meet
Diagonals as shown in dashed lines cross at right angles, and one of the diagonals does bisect the other - cuts equally in half
Please check the attached figure a.
Answer:
3/4
Step-by-step explanation:
15/20=3/4 if you divide both sides by 5
Answer: (-1/4)
Step-by-step explanation:
This divides to -1/4
You probably mean either

or

Write 8 = 2³, so that in the first interpretation,

and in the second,

Then in the first interpretation, we have

Otherwise, the second interpretation gives
