Let
T = theta
Use the Law of Cosines to get
c^2 = a^2+b^2 - 2ab*cos(T)
<span>7^2 = 10^2+8^2 - 2*10*8*cos(T)
</span><span>49 = 164 - 160*cos(T)
-160cos(T) = 49-164
</span><span>-160cos(T) = -115
</span>cos(T) = -115/(-160)
cos(T) = 23/32
cos(T) = 0.71875 which rounds to 0.72
The final answer is C) 0.72
Answer:
(3,3)
Step-by-step explanation:
Given


Required
Determine which can't be any of the new vertices
First, we need to determine the new vertices:

For (0,0):



For (1,0):



For (0,1):



<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>
<em></em>
Answer:
yes it is divisible by 8
Step-by-step explanation:
please mark me as brainlest is
The answer is C. 125.6 in
hope this helps u out!