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3 years ago

A CIRCLE HAS A CIRCUMFENCE 43.96 YD FIND THE RADUIS OF THE CIRCLE

Mathematics

2 answers:

inessss [21]3 years ago

7 0

≈7 I believe that’s the correct answer

zmey [24]3 years ago

6 0

Answer:

≈ 7

Step-by-step explanation:

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abby went to the movies and buy a large container of popcorn. The popcorn container can be modeled by a right circular cone with

DanielleElmas [232]

Answer:

$1.918

Step-by-step explanation:

The volume of a right circular cone is obtained using the formular :

V = 1/3πr²h

From the question:

Diameter = 9 inches ; height = 10 inches

Radius = diameter /2 = 9/2 = 4.5 inches

V = 1/3*π*4.5²*10

V = 211.95 in³

Volume in ft³ = 211.95 / 1728 = 0.12265625 ft³

Density of popcorn = 34 ounces / ft³

Density of popcorn CONTAINER = x

1 ft³ = 34 ounce

0.12265625 ft³ = x

Cross multiply

x = 34 * 0.12265625 ft³

x = 4.1703125 ounce

Hence, popcorn continer has a density of 4.1703125 ounce

If price per container = $8

The price per ounce = $8 / 4.1703125

= $1.918

Hence, price per ounce is $1.918

3 0

3 years ago

What is the result of factoring out the GCF from the expression (24 + 36)?

kap26 [50]

It would be A. 12 is the highest common factor, 24-12 is 12 and 36-12 is 18

5 0

3 years ago

Read 2 more answers

Find the break - even points for company X, which sells all it produces, if the variable cost per unit is $3, fixed costs are $2

ohaa [14]

Given:

The variable cost per unit is $3, fixed costs are $2.

The revenue function is:

$Y_{TR}=5\sqrt{q}$

where q is the number of thousands of units of output produced.

To find:

The break - even points for company X.

Solution:

The variable cost per unit is $3, fixed costs are $2.

So, the cost function is:

Total cost = Fixed cost + Variable cost × Quantity

$Y_{TC}=2+3q$

The revenue function is:

$Y_{TR}=5\sqrt{q}$

At break - even points the profit is zero. It means the cost and revenue are equal.

$Y_{TC}=Y_{TR}$

$2+3q=5\sqrt{q}$

Squaring both sides, we get

$(2+3q)^2=(5\sqrt{q})^2$

$2^2+2(2)(3q)+(3q)^2=25q$

$4+12q+9q^2-25q=0$

$4-13q+9q^2=0$

Splitting the middle term, we get

$4-4q-9q+9q^2=0$

$4(1-q)-9q(1+q)=0$

$(4-9q)(1-q)=0$

Using zero product property, we get

$4-9q=0$ and $1-q=0$

$q=\dfrac{4}{9}$ and $q=1$

$q\approx 0.444$ and $q=1$

Therefore, the break even points are 0.444 and 1.

3 0

3 years ago

Complete this table so that the relationship is propotional

Vedmedyk [2.9K]

Answer:

10 and 60

Step-by-step explanation:

hope this helps :)

7 0

3 years ago

Keith is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than

Marina86 [1]

Answer: 0.0174

Step-by-step explanation:

Given : $\mu=1.85\ \ ; \sigma=0.18$

Let x be the random variable that represents the weight of the drumsticks.

We assume that the weight of the drumsticks is normally distributed.

Now, the z-score for x=2.23 , $\because z=\dfrac{x-\mu}{\sigma}$

$\Rightarrow\ z=\dfrac{2.23-1.85}{0.18}\approx2.11\ \ \$

Using z-value table , we have

P-value =P(x≥2.23)=P(z≥2.11)=1-P(z<2.11)=1-0.9825708

=0.0174292≈0.0174 [Rounded nearest 4 decimal places]

Hence, the probability of the stick's weight being 2.23 oz or greater = 0.0174

6 0

4 years ago