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zhuklara [117]
1 year ago
15

consider a simple ideal rankine cycle with fixed boiler and condenser pressures. what is the effect of superheating the steam to

a higher temperature on
Engineering
1 answer:
Aleonysh [2.5K]1 year ago
3 0

The net work output and cycle efficiency will both increase with superheating the steam. Additionally, the steam at the turbine exit has less moisture in it.

The superheating raises the mean temperature of heat addition, which raises the efficiency of the superheat Rankine cycle over that of the simple Rankine cycle. On the T-s diagram to the left, the impact of decreasing condenser pressure on the Rankine cycle efficiency is depicted. Steam leaves the condenser as a saturated mixture at the saturation temperature corresponding to the condenser pressure. Rankine cycle in thermodynamics Roy Mech's phrase "Superheated" This cycle demonstrates the different phases of operation in a turbine plant using superheated steam. F -> G is a symbol for the turbine's enthalpy reduction. The effect of superheated steam on the Rankine cycle's efficiency is that the efficiency of the cycle rises as the superheat of the steam rises.

Learn more about superheating here:

brainly.com/question/14718830

#SPJ4

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While walking across campus one windy day, an engineering student speculates about using an umbrella as a "sail" to propel a bic
makvit [3.9K]

Answer:

Given data:\\While walking across campus one windy day\\Frontal area, \(A=0.3 m ^{2}\)\\Wind speed \(V=24 Km / hr\)\\The drag coefficient \(C_{D, b}=1.2\)\\The combined mass \(m=75 kg\)\\Umbrella diameter, \(D=1.22 m\)\\Velocity of wind \(V=24 \frac{ km }{ hr }\)\\The rolling resistance \(C_{R}=0.75 \%\)

Solution:

Note: Refer the diagram

Basic equation:\\'s law of motion: \(\sum F_{x}=m a_{x}\)\\Lift coefficient, \(C_{L}=\frac{F_{L}}{\frac{1}{2} \rho V^{2} A_{p}}\)\\Drag coefficient, \(C_{D}=\frac{F_{D}}{\frac{1}{2} \rho V^{2} A_{p}}\)

From force balance equation:\\\(\sum F_{x}=F_{D}-F_{R}=0\)\\But \(F_{D}=\left(C_{D, \alpha} A_{u}+C_{D, B} A_{b}\right) \frac{1}{2} \rho\left(V_{\nu}-V_{b}\right)^{2}\)\(F_{R}=C_{R} m g\)\\Area of the Umbrella \(A_{u}=\frac{\pi D_{u}^{2}}{4}\)\(A_{x}=\frac{\pi \times 1.22^{2}}{4} m ^{2}\)\(A_{v}=1.17 m ^{2}\)

Drag coefficient data for selected objects table at

Hemisphere (open end facing flow), C_{D, x}=1.42

Substituting all parameters,

\begin{aligned}&F_{R}=0.0075 \times 75 \times 9.81\\&F_{R}=5.52 N\end{aligned}

Then,

\begin{aligned}&V_{b}=V_{w}-\left[\frac{2 F_{R}}{\rho\left(C_{D, w} A_{w}+C_{D, B} A_{b}\right)}\right]^{\frac{1}{2}} \dots\\&V_{w}=24 \times 1000 \times \frac{1}{3600}\\&V_{w}=6.67 \frac{ m }{ s }\end{aligned}

And the equation becomes,

\begin{aligned}&V_{b}=6.67-\left[\frac{2 \times 5.52}{1.23(1.42 \times 1.17+1.2 \times 0.3)}\right]^{\frac{1}{2}}\\&V_{b}=6.67-2.11\\&V_{b}=4.56 \frac{ m }{ s }\end{aligned}

Thus the floyds travels at 68.3^{\circ}wind speed.

7 0
4 years ago
A ring-shaped seal, made from a viscoelastic material, is used to seal a joint between two rigid pipes. When incorporated in the
scoundrel [369]
I’m not sure what this question is talking about. I will get back to you later on this let me rethink it. 2.22578
3 0
3 years ago
You will create three classes, the first two being Student and LineAtOfficeHour. The instances of the first class defines a sing
White raven [17]

Answer:

Complete solution is given below:

Explanation:

//student class

class Student{

  private String firstname,lastname;

 

  //constructor

  Student(String first,String last){

      this.firstname=first;

      this.lastname=last;

  }

 

  //getters and setters

  public String getFirstname() {

      return firstname;

  }

  public void setFirstname(String firstname) {

      this.firstname = firstname;

  }

  public String getLastname() {

      return lastname;

  }

  public void setLastname(String lastname) {

      this.lastname = lastname;

  }

  //function to get the fullname of student

  public String fullName() {

      return this.firstname+" "+this.lastname;

  }

}

//class for line at office hour

class LineAtOfficeHour{

 

  private Student line[];

  private int N=0;

  private int back=0;

 

  //empty constructor

  LineAtOfficeHour() {

      line=new Student[5];

  }

  //parameterized constructor

  LineAtOfficeHour(Student st[]) {

      int i=0;

      line=new Student[5];

      while(i<st.length && i<5) {

          line[i]=st[i];

          i++;

      }

      this.N=i;

      this.back=i-1;

  }

  //function to check if line is empty or not

  public boolean isEmpty() {

      if(this.N==0)

          return true;

      else

          return false;

  }

  //function to check if line is full

  public boolean isFull() {

      if(this.N==5) {

          return true;

      }else

          return false;

  }

  ///function to get the size of line

  public int size() {

      return this.N;

  }

 

  //function to add a student to the line

  public void enterLine(Student s) {

      if(isFull())

          System.out.println("Line is full!!!!");

      else {

          line[++back]=s;

          this.N++;

      }

  }

  public Student seeTeacher() {

      Student result=null;

      if(this.N>=0) {

          result=line[0];

          int i=0;

          for(i=1;i<N;i++) {

              line[i-1]=line[i];

          }

          line[i-1]=null;

          this.N--;

          this.back--;

      }

     

     

      return result;

  }

  //function to print students in line

  public String whosInLine() {

      String result ="";

      for(int i=0;i<this.N;i++) {

          result+=line[i].fullName()+",";

      }

      return result;

  }

}

//driver method

public class TestLine {

  public static void main(String[] args) {

      LineAtOfficeHour list=new LineAtOfficeHour();

     

      if(list.isEmpty()) {

          System.out.println("Line is empty!!!!!!!!!");

      }

     

      Student s1[]=new Student[3];

      s1[0]=new Student("John","Smith");

      s1[1]=new Student("Sam","Zung");

      s1[2]=new Student("Peter","Louis");

      list=new LineAtOfficeHour(s1);

     

      if(list.isEmpty()) {

          System.out.println("Line is empty!!!!!!!!!");

      }else {

          System.out.println("Line is not empty.........");

      }

     

      System.out.println("Students in line: "+list.whosInLine());

     

      System.out.println("Student removed: "+list.seeTeacher().fullName());

     

      System.out.println("Students in line: "+list.whosInLine());

  }

}

6 0
4 years ago
Aiman is 80 inches tall. How tall is Aiman in centimeters? Show your work.
harkovskaia [24]
203.2 centimeters.
This is because 1 inch = 2.54 centimeters which means multiply 80 inches X 2.54 = 203.2 centimeters.
5 0
3 years ago
A sheet of steel 2.5 mm thick has nitrogen atmosphere on both sides at 900 oC and is permitted to achieve a steady-state diffusi
DanielleElmas [232]

Answer:

1.8 mm

Explanation:

given data

thick = 2.5 mm

flux = 1 × 10^{-7} kg/m²

high pressure surface is 2 kg/m³

solution

we use fick first law for steady state diffusion

J = D × \frac{Ca - Cb}{Xa - Xb}   ..........1

we take here Ca to point which concentration of nitrogen is 2 kg/m³

so we solve Xb

Xb = Xa + D × \frac{Ca - Cb}{J}

assume Xa = 0 at surface

Xb = 0 + ( 12 × 10^{-11} ) × \frac{2 - 0.5}{1*10^{-7}}

Xb = 1.8 × 10^{-3}

Xb = 1.8 mm

8 0
3 years ago
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