Answer:
471 days
Explanation:
Capacity of Carvins Cove water reservoir = 3.2 billion gallons i.e. 3.2 x 10˄9 gallons
As,
1 gallon = 0.133 cubic feet (cf)
Therefore,
Capacity of Carvins Cove water reservoir in cf = 3.2 x 10˄9 x 0.133
= 4.28 x 10˄8
Applying Mass balance i.e
Accumulation = Mass In - Mass out (Eq. 01)
Here
Mass In = 0.5 cfs
Mass out = 11 cfs
Putting values in (Eq. 01)
Accumulation = 0.5 - 11
= - 10.5 cfs
Negative accumulation shows that reservoir is depleting i.e. at a rate of 10.5 cubic feet per second.
Converting depletion of reservoir in cubic feet per hour = 10.5 x 3600
= 37,800
Converting depletion of reservoir in cubic feet per day = 37, 800 x 24
= 907,200
i.e. 907,200 cubic feet volume is being depleted in days = 1 day
1 cubic feet volume is being depleted in days = 1/907,200 day
4.28 x 10˄8 cubic feet volume will deplete in days = (4.28 x 10˄8) x 1/907,200
= 471 Days.
Hence in case of continuous drought reservoir will last for 471 days before dry-up.
Answer:
See the detailed answer in attached file.
Explanation :
When electric power is transferred over a long distance then, line loss can be reduced by high voltage and low current. Thus, option A is correct.
<h3>What is electric power?</h3>
The complete question is attached to the image below.
The electric circuit transfers the electric current then it is called electric power. The loss in the line over a larger distance is reduced by transferring AC instead of DC voltage.
The AC transmitted is of high voltage, and the power is low. The equation for current is given,
P = VI
The increase in the voltage causes the decrease in the current and in turn the resistance also reduces resulting in the loss of the power of the circuit to decrease.
Therefore, the loss is reduced by transferring high voltage and, low current AC.
Learn more about high volatge AC here:
brainly.com/question/18069892
#SPJ1