Answer:
Option-A
Explanation:
Pentose phosphate pathway is the alternative pathway taking place in both eukaryotes and prokaryotes parallel to the glycolysis.
The pentose phosphate pathway forms the electron carriers called NADPH and the ribose-5 phosphate.
The NADPH is formed in large amounts through this pathway which contains a very high amount of energy. NADPH can donate its hydride ions, therefore, it can be involved in the reaction where it can donate energy in the form of hydrogen and electron.
The NADPH is therefore involved in the formation of reducing biosynthetic pathways like fatty acid synthesis, cholesterol synthesis, and bile acid synthesis.
Thus, Option-A is the correct answer.
Answer:
The correct answer is- IgA
Explanation:
There are five types or class of antibodies found in the human body these are IgA, IgM, IgD, IgE, and IgG. Out of these five class IgA antibody is found in an abundant amount in the mother's milk or colostrum.
Infant take this antibody from the mother through breastfeeding which protects the infant from may pathogenic microbes. The immunity in which antibodies are taken from outside is called passive immunity.
Therefore the passive immunity source that is given by the mother to baby through breast milk is called IgA.
Answer:
do it in your self hahahahahaa
Answer:
GG, Gg, Gg, gg
Homozygous green – GG
Heterozygous green – Gg
Homozygous yellow - gg
Explanation:
It is given that allele for green seed pods (G) is dominant to the allele for yellow seed pods (g) which means that if “G” and “g” occur together, a trait associated with G will be expressed.
The genotype of the true breeding Green plant is “GG”
The genotype of the true-breeding yellow plant is “gg”
F1 generation cross
GG * gg
Offspring produced from F1 generation are – Gg, Gg, Gg, Gg
In f2 generation offspring of F1 generation are crossed among each other.
So the offspring produced in F2 generation are
Gg * Gg
GG, Gg, Gg, gg
Homozygous green – GG
Heterozygous green – Gg
Homozygous yellow - gg
