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GREYUIT [131]
3 years ago
9

Xavier surveyed a random sample of the grade levels of the Spanish Club members in the county. The bar graph shows the results o

f his survey.
The bar graph is titled Random Sample of Spanish Club Members. The horizontal axis is labeled Grade level and lists four grades: ninth to twelfth. The vertical axis is labeled Number of members from zero to fourteen by twos. Ninth, eight. Tenth, fourteen. Eleventh, five. Twelfth, three.

Of the 300 students in the Spanish Club in the county, predict how many are 9th graders

Mathematics
2 answers:
pishuonlain [190]3 years ago
8 0

Answer:

80

Step-by-step explanation:

If you add each value it equals 30.

30x10=300 so 8 (value of the 9th grade bar) times 10 equals 80.

Svet_ta [14]3 years ago
8 0
The answer would be 80 !
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For a standard normal distribution (µ=0, σ=1), the area under the curve less than 1.25 is 0.894. What is the approximate percent
Nesterboy [21]

Answer:

10.6%

Step-by-step explanation:

Normal curves are symmetrical.  That means that on a standard normal distribution,  the area less than -1.25 is the same as the area greater than +1.25.  The total area under the curve is 1, so:

P = 1 - 0.894

P = 0.106

Approximately 10.6% of the area under the curve lies below -1.25.

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4 years ago
After retirement from the service a man received some amount from his provident fund. He gave two-fifth of the amount to his son
Fed [463]

Answer:

F

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2 years ago
Helppppp and show equation plsssssssss
laiz [17]

Answer:

24

Step-by-step explanation:

6+2×3+4+(27-19)

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and then the multiplication, 2×3 = 6

then the addition, 6+6+4+8 = 24

4 0
3 years ago
does somebody knows how to do this one?
vlada-n [284]

Answer:

Step-by-step explanation:

To find the area subtract the area of the semicircle from the area of the rectangle.

Although the line isn’t there, if you imagine there is one, then you will see that you form a rectangle which is the same line as the semicircle’s diameter.

The area of rectangle is:

⇒ A = lw

⇒ A = (14)(8)

⇒ A = 112cm^{2}

The area of the semicircle;

⇒ A = \frac{1}{2}\pi r^{2}

⇒ A = \frac{1}{2}\pi (7)^{2}

*Note here that the radius is half the diameter, so it is 7cm, not 14cm

⇒ A = 76.97cm^{2}

Finally subtract the two areas;

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⇒ A = 35.03cm^{2}

6 0
2 years ago
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