Answer: It would be the boiling point.
Explanation:
Because it is not a liquid nor a gas, that would mark the last two out. I'll have to guess that it is the boiling point of water.
Answer:
One of the main functions lipids do is storing energy.
provide the building blocks for muscle tissue
Answer:
The trick here is to realize that the nitride anion, N3− , is isoelectronic with neon, Ne , the noble gas that shares a period with nitrogen, N . In other words, the nitride anion has the same number of electrons as neon.J
Explanation:
Answer: Nuclei combine to form a heavier nucleus, releasing energy.
Explanation: e.g two deuterium nucleus (Hydrogen-2 isotopes) forms an He nucleus and energy is released.
Answer:
![x_{CO_{2}}=11/25=0.44\\x_{H_{2}O}=2.25/25=0.09\\x_{O_{2}}=11.6/25=0.464](https://tex.z-dn.net/?f=x_%7BCO_%7B2%7D%7D%3D11%2F25%3D0.44%5C%5Cx_%7BH_%7B2%7DO%7D%3D2.25%2F25%3D0.09%5C%5Cx_%7BO_%7B2%7D%7D%3D11.6%2F25%3D0.464)
Explanation:
First we need to to set and balance the equation:
![2H_{2}+4CO_{2}+5O_{2}\longrightarrow 4CO_{2}+2H_{2}O+2O_{2}](https://tex.z-dn.net/?f=2H_%7B2%7D%2B4CO_%7B2%7D%2B5O_%7B2%7D%5Clongrightarrow%204CO_%7B2%7D%2B2H_%7B2%7DO%2B2O_%7B2%7D)
With this we can balance the equation with our molar fractions, and we will asume 1 mole of mixture at the beginning for practical purposes:
![0.2H_{2}+0.25CO_{2}+0.55O_{2}\longrightarrow ?CO_{2}+?H_{2}O+?O_{2}](https://tex.z-dn.net/?f=0.2H_%7B2%7D%2B0.25CO_%7B2%7D%2B0.55O_%7B2%7D%5Clongrightarrow%20%3FCO_%7B2%7D%2B%3FH_%7B2%7DO%2B%3FO_%7B2%7D)
With the equation we need to balance with the limit reactant, that is CO:
![0.125H_{2}+0.25CO_{2}+0.3125O_{2}\longrightarrow 0.25CO_{2}+0.125H_{2}O+0.125O_{2}](https://tex.z-dn.net/?f=0.125H_%7B2%7D%2B0.25CO_%7B2%7D%2B0.3125O_%7B2%7D%5Clongrightarrow%200.25CO_%7B2%7D%2B0.125H_%7B2%7DO%2B0.125O_%7B2%7D)
Now we just need to operate with the fractions that we have:
![m_{i}=(0.2*2)+(0.25*28.01)+(0.55*32)=25 g\\m_{f}=25g](https://tex.z-dn.net/?f=m_%7Bi%7D%3D%280.2%2A2%29%2B%280.25%2A28.01%29%2B%280.55%2A32%29%3D25%20g%5C%5Cm_%7Bf%7D%3D25g)
We proceed to calculate the mass of each product at the end with the moles of the balanced equation, remember that we had an excess of oxygen at the beginning, so we need to add that excess at the end:
![n_{CO_{2}}=0.25\\n_{H_{2}O}=0.125\\n_{O_{2}}=0.3625\\m_{CO_{2}}=0.25*44.01=11g\\m_{H_{2}2}=0.125*18=2.25g\\m_{O_{2}}=0.3625*32=11.6g](https://tex.z-dn.net/?f=n_%7BCO_%7B2%7D%7D%3D0.25%5C%5Cn_%7BH_%7B2%7DO%7D%3D0.125%5C%5Cn_%7BO_%7B2%7D%7D%3D0.3625%5C%5Cm_%7BCO_%7B2%7D%7D%3D0.25%2A44.01%3D11g%5C%5Cm_%7BH_%7B2%7D2%7D%3D0.125%2A18%3D2.25g%5C%5Cm_%7BO_%7B2%7D%7D%3D0.3625%2A32%3D11.6g)
Now that we have the masses of each product, and the total mass, we can calculate the fraction:
![x_{CO_{2}}=11/25=0.44\\x_{H_{2}O}=2.25/25=0.09\\x_{O_{2}}=11.6/25=0.464](https://tex.z-dn.net/?f=x_%7BCO_%7B2%7D%7D%3D11%2F25%3D0.44%5C%5Cx_%7BH_%7B2%7DO%7D%3D2.25%2F25%3D0.09%5C%5Cx_%7BO_%7B2%7D%7D%3D11.6%2F25%3D0.464)