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stepan [7]
2 years ago
10

Pretend you are the size of an atom and you are observing a reaction between a potassium ion and a fluorine atom. Describe how a

n ionic bond forms as the atoms react. Tell what happens to the valence electrons in each atom and how each atom is changed by losing or gaining electrons.
Chemistry
2 answers:
Oliga [24]2 years ago
8 0

Answer:

C

Explanation:

Elena L [17]2 years ago
6 0
Due to periodic trends potassium would lose its one valence electron to have a more stable electron configuration equivalent to that of argon, which is a noble gas with a full octet. Fluorine would gain one valence electron to get a full octet equivalent to that of neon. Since potassium lost an electron it now has a positive charge and since fluorine gained an electron it is now negative. Since both are more stable this way as a full octet they will no longer exchange electrons but the positive potassium and negative fluorine will pull towards each other strongly forming an ionic bond.
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1 year ago
The percentage yield for the reaction
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Answer:

92.87 g.

Explanation:

∵ The percentage yield = (actual yield/theoretical yield)*100.

  • We need to calculate the theoretical yield:

From the balanced reaction:

<em>PCl₃ + Cl₂ → PCl₅,</em>

It is clear that 1 mol of PCl₃ reacts with 1 mol of Cl₂ to produce 1 mol of PCl₅.

  • We need to calculate the no. of moles of 73.7 g PCl₃:

n = mass/molar mass = (73.7 g)/(137.33 g/mol) = 0.536 mol.

<u><em>Using cross multiplication:</em></u>

1 mol of PCl₃ produce  → 1 mol of PCl₅, from stichiometry.

∴ 0.536 mol of PCl₃ produce  → 0.536 mol of PCl₅.

∴ The mass of PCl₅ (theoretical yield) = (no. of moles) * (molar mass) = (0.536 mol)*(208.24 g/mol) = 111.62 g.

<em>∵ The percentage yield = (actual yield/theoretical yield)*100.</em>

The percentage yield = 83.2%, theoretical yield = 111.62 g.

∴ The actual yield of PCl₅ = (The percentage yield)(theoretical yield)/100 = (83.2%)(111.62 g)/100 = 92.87 g.

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