Rate law for the given 2nd order reaction is:
Rate = k[a]2
Given data:
rate constant k = 0.150 m-1s-1
initial concentration, [a] = 0.250 M
reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s
To determine:
Concentration at time t = 300 s i.e. ![[a]_{t}](https://tex.z-dn.net/?f=%5Ba%5D_%7Bt%7D)
Calculations:
The second order rate equation is:
![1/[a]_{t} = kt +1/[a]](https://tex.z-dn.net/?f=1%2F%5Ba%5D_%7Bt%7D%20%3D%20kt%20%2B1%2F%5Ba%5D)
substituting for k,t and [a] we get:
1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M
1/[a]t = 49 M-1
[a]t = 1/49 M-1 = 0.0204 M
Hence the concentration of 'a' after t = 5min is 0.020 M
The grams of oxygen that are required to produce 1 mole of H₂O is 16 g ( answer B)
<u><em> calculation</em></u>
2 CH₄ + 2NH₃ +3 O₂ → 2HCN + 6H₂O
step 1: use the mole ratio to find moles of O₂
from equation above the mole ratio of O₂: H₂O is 3:6 therefore the moles of O₂ = 1 mole x3/6 =0.5 moles
step 2: find mass of O₂
mass= moles x molar mass
from periodic table the molar mass of O₂ = 16 x2= 32 g/mol
mass O₂ = 0.5 moles x 32 g/mol = 16 g (answer B)
Answer:
Chadwick-he discovered the neutron. He discovered this by demonstrating a neutral particle with a mass the same as a proton through a reaction between gramma Ray's and a wax sample.
Rutherford-he discovered the concept of radioactive half-life, the radioactive element radon, and named alpha and beta radiation.
j.j.Thompson discovered that atoms where made up of smaller components. This had major effects for the field of physics.
:)
d G = 2 (dG NOCl) - 2 (dG NO)
= 2 * 66.08 - 2 * 87.6 = -43.04 kJ /mol
dG = - 2.303 RT log K
-43.04 = - 2.303 RT log K
7.54 = log K
K = 3.42 * 10^7
Kp = k (RT)^dn
d n = 2 - 1 -2 = -1
Kp = (3.42 * 10^7) (8.314 * 298)^-1
Kp = 1.31 * 10^4
Answer:
A neutral solution hope it helps
