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ivanzaharov [21]
4 years ago
11

Part A

Mathematics
1 answer:
lawyer [7]4 years ago
5 0

Answer:

Mei took 9 more strokes than Noah

Step-by-step explanation:

HOPE THIS HELPED! ;D

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Find the sum of 12a + 7b, −6a − 9, and 14a − 12b.
Ivan
The answer is:  [A]:  " 20a − 5b − 9 " .
______________________________________
Explanation:
_______________________________________________
  (12a <span>+ 7b) + (−6a − 9) + (14a − 12b) =
 
   12a </span><span>+ 7b  +  1(−6a − 9) + 1(14a − 12b) =
</span>    
   12a + 7b + (1*-6a) + (1*-9) + (1*14a) + (1* -12b) =
      
    12a + 7b − 6a − 9 + 14a − 12b =  ?

Combine the "like terms:

12a − 6a  + 14a = 20a ; 

7b − 12b =  - 5b ;

and then we have "-9" ;
_____________________________________________________
So, write as:   " 20a − 5b − 9 " ;  which is:  Answer choice:  [A].
______________________________________________________
8 0
3 years ago
Read 2 more answers
a person kicks a ball from the ground into the air with an initial upward velocity of 8 feet per second. what is the maximum hei
KengaRu [80]
Chech the picture below.

if the person kicked it from the ground, that means its initial height is 0.

it reaches its maximum height at the y-coordinate of its vertex, and it will hit the ground when y = 0, as you see in the picture.

\bf ~~~~~~\textit{initial velocity}&#10;\\\\&#10;\begin{array}{llll}&#10;~~~~~~\textit{in feet}&#10;\\\\&#10;h(t) = -16t^2+v_ot+h_o&#10;\end{array} &#10;\quad &#10;\begin{cases}&#10;v_o=\stackrel{8}{\textit{initial velocity of the object}}\\\\&#10;h_o=\stackrel{0}{\textit{initial height of the object}}\\\\&#10;h=\stackrel{}{\textit{height of the object at "t" seconds}}&#10;\end{cases}&#10;\\\\\\&#10;h(t)=-16t^2+8t+0

now let's find the y-coordinate of its vertex

\bf \textit{vertex of a vertical parabola, using coefficients}&#10;\\\\&#10;h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+8}t\stackrel{\stackrel{c}{\downarrow }}{+0}&#10;\qquad \qquad &#10;\left(-\cfrac{ b}{2 a}~~~~ ,~~~~  c-\cfrac{ b^2}{4 a}\right)&#10;\\\\\\&#10;\left(\qquad ,~~0-\cfrac{8^2}{4(-16)}  \right)\implies (\quad ,~0+1)\implies (\quad ,~1)

when will it hit the ground?

\bf \stackrel{h(t)}{0}=-16t^2+8t\implies 16t^2-8t=0\implies 8t(2t-1)=0&#10;\\\\\\&#10;8t=0\implies \stackrel{\textit{0 seconds when it took off first}}{t=0}&#10;\\\\\\&#10;2t-1=0\implies 2t=1\implies \stackrel{\textit{half a second later it  when it came back down}}{t=\cfrac{1}{2}}

3 0
3 years ago
Solve the system. 9=4x-2y 2x+6=y
Digiron [165]

Step-by-step explanation:

4x-2y = 9 ...1

2x-y = -6 ...2

if ...2 × 2

4x-2y = -12

9 is not equal to -12

4 0
2 years ago
Im giving 100 Points to anyone who could solve this for me please.
myrzilka [38]

Answer:

AB = 27.2

BC = 33.5

AC = 50.4

∠A = 38°

∠ABC = 112°

Step-by-step explanation:

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

\implies \sf \cos(30^{\circ})=\dfrac{29}{BC}

\implies \sf BC=\dfrac{29}{\cos(30^{\circ})}

\implies \sf BC=\dfrac{58\sqrt{3}}{3}=33.5\:(nearest\:tenth)

\implies \sf \tan(30^{\circ})=\dfrac{BD}{29}

\implies \sf BD=29\tan(30^{\circ})

\implies \sf BD=\dfrac{29\sqrt{3}}{3}

\implies \sf \sin(38^{\circ})=\dfrac{BD}{AB}

\implies \sf AB=\dfrac{\dfrac{29\sqrt{3}}{3}}{\sin(38^{\circ})}

\implies \sf AB=27.2\:(nearest\:tenth)

\implies \sf \tan(38^{\circ})=\dfrac{BD}{AD}

\implies \sf AD=\dfrac{\dfrac{29\sqrt{3}}{3}}{\tan(38^{\circ})}

\implies \sf AD=21.4\:(nearest\:tenth)

\implies \sf AC=AD+DC=21.4+29=50.4

The interior angles of a triangle sum to 180°

⇒ ∠A + 52° + 90° = 180°

⇒ ∠A = 180° - 90° - 52°

⇒ ∠A = 38°

⇒ ∠ABC + 38° + 30° = 180°

⇒ ∠ABC = 180° - 38° - 30°

⇒ ∠ABC = 112°

**I have checked the measures using a graphing programme - see attached**

8 0
2 years ago
Bill wants to bould a shed that is 2 feet longer than it is wide. Then he want to fence in a pasture area using 2 sides of the s
soldier1979 [14.2K]
To answer this item, I would assume that the pasture is in a rectangular form. The area of a rectangle is the product of the dimensions. Let x be one of the sides of the pasture and the other dimension will become x+2. The equation that would best represent the scenario is,
                                      <em>A = (x)(x + 2)</em>
7 0
3 years ago
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