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Tema [17]
2 years ago
12

Hii! please help i’ll give brainliest

Mathematics
1 answer:
Dafna11 [192]2 years ago
3 0

Answer

east

Step-by-step explanation:

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My has 3 times more books that grant , and grant has 6 f
Klio2033 [76]

I’m not sure what happened while you were writing this, but if I’m reading it right, “My” has 18 books. If “My” has 3 times as many as 6, that also means 3 times 6, which is 18.


7 0
2 years ago
What is the volume of this?
yawa3891 [41]
Hello there.

Answer: Split the shape into two
Calculate both shapes separately
10 x 10 x 10 = 1000
20 x 20 x 20 = 8000.
Add together both values:
8000 + 1000 = 9000in³

Hope Thus Helps You!
Good Luck Studying ^-^
4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
aleksley [76]

The length of PR is 4.4 units.

Explanation:

It is given that the length of the hypotenuse is 10 units.

Also, the angle of R is 64°

To find the length of PR, we shall use the cosine formula,

\cos \theta=\frac{a d j}{h y p}

Here,  \theta=64, adj = PR and hyp = 10

Substituting these values in the formula, we get,

\cos 64=\frac{P R}{10}

Multiplying both sides by 10, we get,

10*\cos 64={P R}

Substituting the value for cos 64, we get,

10*0.438={P R}

Multiplying, we have,

4.38=PR

Rounding off, we get,

PR=4.4

Thus, the length of PR is 4.4 units.

8 0
3 years ago
What is the volume of the composite figure? Round your answer to the nearest hundredth. Use 3.14 for π.
Reil [10]

Answer:

<em><u>263.76</u></em><em><u> </u></em><em><u>in</u></em><em><u>^</u></em><em><u>3</u></em>

VOLUME OF FIGURE=VOL.OF CONE+VOL.OF CYLINDER +VOL.OF HEMISPHERE

=(1/3×3.14×3×3×4)+(3.14×3×3×6)+(2/3×3.14×3×3×3)

=37.68+169.56+56.52

=263.76in^3

7 0
2 years ago
I need help!! Find the area of each shaded segment. Round your answer to the nearest 10th
guajiro [1.7K]

Given:

θ = 60°

Radius = 8 in

To find:

The area of the shaded segment.

Solution:

Vertically opposite angles are congruent.

Angle for the shaded segment = 60°

<u>Area of the sector:</u>

$A=\pi r^2\times \frac{\theta}{360^\circ}

$A=3.14 \times 8^2\times \frac{60^\circ}{360^\circ}

A = 33.5 in²

Area of the sector = 33.5 in²

<u>Area of triangle:</u>

$A=\frac{1}{2} bh

$A=\frac{1}{2} \times 8\times 8

A = 32 in²

Area of the triangle = 32 in²

Area of segment = Area of sector - Area of triangle

                            = 33.5 in² - 32 in²

                            = 1.5 in²

The area of the shaded segment is 1.5 square inches.

8 0
3 years ago
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