The number of students in Mr. Boggs’s homeroom is equal to b. Add the total number of students in each class and set it equal to 90.
90 = b + 1.5(b + 2) + 15 + (2b – 9)
Use the Distributive Property, and collect like terms. 90 = b + 1.5b + 3 + 15 + 2b – 9
90 = 4.5b + 9
The answer to this question is false that's the answer
The first one because it’s (13(31)
Answer:
C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.
Step-by-step explanation:
Let μ be the the average attendance at games of the football team
The claim: the average attendance at games is over 523
Null and alternative hypotheses are:
: μ=523
: μ>523
The conclusion is failure to reject the null hypothesis.
This means that <em>test statistic</em> is lower than <em>critical value</em>. Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.
That is no significant evidence that the average attendance at games of the football team is greater than 523.
Answer:
5.5 miles over 2 hours--> 5.5/2= 2.75 miles per hour was his average walking speed. 5.5 miles over 2.5 hours --> 5.5/2.5= 2.2 miles per hour on the return trip meaning that his average speed was (2.75-2.2= 0.55) 0.55 miles per hour lower on the return trip
Step-by-step explanation:
I hope this helps you :)
<em><u>-KeairaDickson</u></em>