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3 years ago

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The equation of line AB is (y-3)= 5(x-4). What is the slope of a line perpendicular to line AB?

1 answer:

Tcecarenko [31]3 years ago

4 0

*Hint: When the slope of a line is perpendicular, it would have the negative reciprocal.

First, let's simplify this equation into y = mx + b format.

y - 3 = 5(x - 4)
y - 3 = 5x - 20
y = 5x - 17

Since 5 is the slope of this equation, the negative reciprocal would be -1/5.

Answer: -1/5

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A train travels at a constant rate of 40 miles per hour. How many miles will it travel in 3 hours?

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Step-by-step explanation:

1) If you really meant X^2+12=40, then this simplifies to x^2 = 28, and therefore x = ±√28, or x = ±2√7.

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Please help me ASAP!Please this is due soon and i don't have all day.

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<u><em>Answer:</em></u>

Section 1: 5.59%

Section 2: -2.16%

Section 3: -10.82%

Section 4: -6.54%

Section 5: -2.16%

Section 6: 7.86%

<u><em>Explanation:</em></u>

<u>The formula to calculate the percent change in mass is given as:</u>

$PercentChange = \frac{ChangeInMass}{StartingMass}*100=\frac{NewMass - OldMass}{OldMass}*100$

<u>1- Section 1:</u>

Old mass = 7.83 g and New mass = 8.268 g

$PercentChange = \frac{8.268-7.83}{7.83}*100 =$ 5.59%

<u>2- Section 2:</u>

Old mass = 7.4 g and New mass = 7.24 g

$PercentChange = \frac{7.24-7.4}{7.4}*100 =$ -2.16%

<u>3- Section 3:</u>

Old mass = 7.3 g and New mass = 6.51 g

$PercentChange = \frac{6.51-7.3}{7.3}*100 =$ -10.82%

<u>4- Section 4:</u>

Old mass = 7.49 g and New mass = 7.0 g

$PercentChange = \frac{7.0-7.49}{7.49}*100 =$ -6.54%

<u>5- Section 5:</u>

Old mass = 7.4 g and New mass = 7.24 g

$PercentChange = \frac{7.24-7.4}{7.7.4}*100 =$ -2.16%

<u>6- Section 6:</u>

Old mass = 7.89 g and New mass = 8.51 g

$PercentChange = \frac{8.51-7.89}{7.89}*100 =$ 7.86%

Hope this helps :)

6 0

3 years ago