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Sauron [17]
1 year ago
14

Please HELP!!!!! 100% giving brainliest!!!! I'm givining 100 points too!!!!!!!!

Chemistry
2 answers:
Papessa [141]1 year ago
6 0

Answer:

This would be my answer and I hope this helps you.

observe that the flame is not touching the solid candle or the melted wax. It appears to be only touching the wick. I ask them if they think that the candle would burn as long if it were only the wick that was burning. What is the purpose of the wax? When the students place the first flame into the smoke of the second candle, they should see the second candle relight. It is not necessary to touch the wick in order for it to relight. This should lead them to conclude that it is the wax vapor that is burning.

When the students place the beaker containing the ice water above the candle, they should see condensation on the bottom of the beaker. If they hold it too close, they will not see the condensation and will see soot form. Students will usually recognize that the condensation is made of water, but they have difficulty recognizing that it comes from the combustion of the candle.

When the Erlenmeyer flask is placed over the top of the candle in the water, student should observe that the water candle goes out and the water rises. The students test the gas that was collected with phenol red solution (an acid-base indicator). They should observe that the solution changes from red to yellow. I demonstrate that this might indicate the formation of carbon dioxide by blowing through a straw into a solution of phenol red.

Explanation:

Hope this helped you!And thanks for inviting me to be your friend!(:

vampirchik [111]1 year ago
3 0

Answer:

The wax vapor starts to burn and creates the stable candle flame that you see. When you blew out the candle you should have seen white smoke rising up into the air from the wick. This is the wax vapor, which becomes visible as it condenses into small liquid droplets in the cooler air.

Explanation:

hope it helps

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2 AgNO3(aq) + CaCl2(aq) -----&gt; 2 AgCl(s) + Ca(NO3)2(aq)
yan [13]

5.732 grams of AgCl is formed when 0.200 L of 0.200 M AGNO3 reacts with an excess of CaCl2.

Explanation:

The balanced equation:

2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)

data given:

volume of AgNO3 = 0.2 L

molarity of AgNO3 = 0.200 M

atomic weight of AgCl= 143.32 gram/mole

from the formula, number of moles can be calculated

Molarity = \frac{number of moles}{volume in litres}

number of moles of AgNO3 = 0.04

From the reaction:

2 moles of AgNO3 reacts to form 2 moles of AgCl

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\frac{2}{2} = \frac{x}{0.04}

= 0.04 moles of AgCl is formed

mass of AgCl formed is calculated by multiplying number of moles with atomic mass of AgCl

mass of AgCl = 0.04 x 143.32

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