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ElenaW [278]
3 years ago
5

In relation to the reactants of a chemical reaction, the products are

Chemistry
2 answers:
Sav [38]3 years ago
8 0
In a chemical reaction, the products should always be equal to the reactants (in this case you would answer “the same as the reactants”) since we can neither create nor destroy matter (law of conservation!)


Hope this helps! :)
Viktor [21]3 years ago
8 0

Answer:

The answer is D) different from the reactants

Explanation:

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Question: What is the formula of Potassium hydroxide? What is it common name? Is it Alkali?

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3 years ago
A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill
LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)

Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%

This means in 10.0 g, we have a total of:

m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

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The particles can move around each other because they do not have as strong bonds as solids do.
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