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Kobotan [32]
1 year ago
5

What value does "h" have in this equation for this to be an infinite solutions equation. 6 (hx + 5) + 4 = -4(8 - 4(8 – 18x) 18x)

+ 66

Mathematics
1 answer:
Sever21 [200]1 year ago
4 0

We have the following:

6(hx+5)+4=-4(8-18x)+66

A system of linear equations has infinite solutions when the graphs are exactly the same line.

for this to happen, on both sides the value of x must be equal:

\begin{gathered} 6\cdot h=4\cdot18 \\ h=4\cdot\frac{18}{6} \\ h=12 \end{gathered}

replacing:

\begin{gathered} 6\cdot(12x+5)+4=-4\cdot(8-18x)+66 \\ 72x+30+4=-32+72x+66 \\ 7x+34=7x+34 \\ 0=0 \\ \text{true for all x} \end{gathered}

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Answer:

9x+2y+6+9y+7

9x+2y+9y+6+7

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A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 441 gram setting. Based
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Answer:

Conclusion: Fail to Reject Null Hypothesis          

We conclude that the bags are not overfilled.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 441 gram

Sample mean, \bar{x} = 448 gram

Sample size, n = 19

Alpha, α = 0.01

Sample standard deviation, s = 27 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 441\text{ grams}\\H_A: \mu > 441\text{ grams}

We use One-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{448 - 441}{\frac{27}{\sqrt{19}} } = 1.13

Now,

t_{critical} \text{ at 0.01 level of significance, 18 degree of freedom } = 2.55

Since,                  

t_{stat} < t_{critical}

We reject null hypothesis when t > 2.55

We accept the null hypothesis and fail to reject it. Thus, we conclude that the bags are not overfilled.

8 0
3 years ago
Riya is applying mulch to her garden. she applies it at a rate of 250 , 000 cm 3 250,000 cm 3 250, comma, 000, start text, space
Tatiana [17]

The rate in

\frac{ {m}^{3} }{ {m}^{2} }  \: is \:0.25\frac{ {m}^{3} }{ {m}^{2} }

<h3>How to find rate is riya applying mulch in m^3/m^2 ?</h3>

given that riya applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space.

we already know that 1m = 100cm.

so, each side of this cube is 100cm in length.

so,100 \times 100 \times 100 \: {cm}^{3}  \: in \:  {m}^{3}

To find what is the volume in cubic metres.

\frac{250000}{10000000}  =  \frac{1}{4}  = 0.25 \frac{ {m}^{3} }{ { m}^{2} }

so, the rate is0.25 \frac{ {m}^{3} }{ {m}^{2} }

Learn more about problems on garden, refer :

https://brainly.in/question/50618467

#SPJ4

Disclaimer : This question was given incomplete on portal.Here is complete question.

Question : Riya is applying mulch to her garden.She applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space. At what rate is riya applying mulch in m^3/m^2

8 0
2 years ago
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