PLEASE HELP WILL GIVE BRAINLIEST
1 answer:
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Answer:
0.40
Step-by-step explanation:
to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8
Let A = sum of dice is 8
B = one lands in 5
P(B/A) = P(AB)/P(A) by conditional probability
P(AB) = sum is 8 and one is 5
So (5,3) or (3,5)
P(A) = sum is 8.
i.e. (2,6) (2,6) (3,5) (5,3) (4,4)
Required probability
= n(AB)/n(A)
=
Answer:
48 ways
Step-by-step explanation:
Let me take a guess
S₁_₁₅ = (1+15)*7 + 8 = 120
There are 48 combinations of distinct digits from 1 to 15 to make 20
120-20=100
So every 20 has a corresponding 100
I wish I got it right, otherwise report it.
