point a is on line segment RT. Given ST = 2x, RT = 4x, and RS = 4x -4 determine the numerical length of RS

HI PLS HURRY !!

VARVARA [1.3K]

Step-by-step explanation:

234751

100% sure

Goood luck.

5 0

2 years ago

G−9=−19<br><br> What does g=???

Free_Kalibri [48]

Answer:

g=-19+9

g=-10

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Solve for x. 4(2-x)+13=2x+3

gregori [183]

Answer:

x = 3

Step-by-step explanation:

4(2-x)+13=2x+3

distribute the 4.

8 - 4x + 13 = 2x + 3

combine like terms.

21 - 4x = 2x + 3

18 = 6x

divide by 6.

x = 3

check.

4(2 - 3) + 13 = 2(3) + 3

4(-1) + 13 = 6 + 3

-4 + 13 = 9

9 = 9

correct!

4 0

2 years ago

One month Ravi rented4 movies and8video games for a total of $57 The next month he rented2 movies and3 video games for a total o

e-lub [12.9K]

SOLUTION

Given the question in the question tab, the following are the solution steps to get the rental cost for each movie and each video game.

Step 1: Write the representation for the two rentals

Let m represents movies

Let v represent video games

Step 2: Write the statements in form of a mathematical equation

$\begin{gathered} \text{Month 1: }4m+8v=57 \\ \text{Month 2: }2m+3v=23 \end{gathered}$

Step 3: Solve the equations above simultaneously using elimination method to get the values of m and v

$\begin{gathered} 4m+8v=57----(1) \\ 2m+3v=23----(2) \\ \text{ multiply equation 1 by 2 and equation 2 by }4 \\ 8m+16v=114----(3) \\ 8m+12v=92----(4) \\ \text{subtract equation (4) from equation (3)} \\ 4v=22 \\ v=\frac{22}{4}=5.5 \\ \text{Substitute 5.5 for v in equation 1 to get the value of m} \\ 4m+8v=57 \\ 4m+8(5.5)=57 \\ 4m+44=57 \\ 4m=57-44=13 \\ m=\frac{13}{4}=3.25 \\ m=\text{\$}3.25,v=\text{\$}5.50 \end{gathered}$

Rental cost for each movies is $3.25

Rental cost for each video games $5.50

8 0

1 year ago

How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy

Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

$n \cdot (n+1) < 40000$

Now we solve this inequation to the highest value of $n$ that satisfy the inequation:

$n^{2}+n < 40000$

$n^{2}+n -40000$

The Quadratic Formula shows that roots are:

$n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}$

$n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}$

$n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}$

$n_{1} \approx 199.501$

$n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}$

$n_{2} \approx -200.501$

Only the first root is valid source to determine the highest possible value of $n$ , which is $n_{max} = 199$ . Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0

2 years ago