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mojhsa [17]
3 years ago
11

point a is on line segment RT. Given ST = 2x, RT = 4x, and RS = 4x -4 determine the numerical length of RS

Mathematics
1 answer:
Andrei [34K]3 years ago
3 0
Forty nine x plus 15x -ggsg and y will get 13
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A 14-foot ladder is leaning against the side of a house.The angle the ladder makes with the ground is 50 degrees. How far is the
VashaNatasha [74]

Answer:

9 ft

Step-by-step explanation:

You can use cosine to solve this, which is adjacent over hypotenuse. The ladder forms a triangle with the house, and the side you need to solve for is adjacent to the angle. You can set up the equation:

cos(50)=x/14

Then you multiply 14 by cos(50) and get almost 9 ft (rounding to the nearest tenth of a foot).

6 0
3 years ago
What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)? (5 points) y = 4x − 2 y = 2x − 4 y = −3(
DIA [1.3K]

For this case we have that by definition, the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

We have the following points:

(x_ {1}, y_ {1}) :( 2,6)\\(x_ {2}, y_ {2}) :( 4,0)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0-6} {4-2} = \frac {-6} {2} = -3

We chose a point:

(x_ {0}, y_ {0}) :( 4,0)

Substituting in the equation we have:

y-0 = -3 (x-4)\\y = -3 (x-4)

Finally, the equation is: y = -3 (x-4)

Answer:

OPTION C

6 0
3 years ago
Read 2 more answers
Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an
Leya [2.2K]
Parameterize the lateral face T_1 of the cylinder by

\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v

where 0\le u\le2\pi and 0\le v\le3, and parameterize the disks T_2,T_3 as

\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)
\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)

where 0\le r\le2 and 0\le\theta\le2\pi.

The integral along the surface of the cylinder (with outward/positive orientation) is then

\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS
=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr
=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr
=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr
=136\pi
7 0
3 years ago
Please help me as soon as possible
Alex777 [14]

Answer:

I think the choose (B)

5x/x + 3/x

5 0
2 years ago
Read 2 more answers
If 210 people said football was their favorite sport to watch how many people were surveyed.
Anarel [89]
I would say 110 becuz if u add all of those together u would get 100 then u find a number that will get you to 210 which would be 110 then u get 210 ..hope this helps sorry if not
5 0
2 years ago
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