Answer: 2.93 ft/sec
Explanation: Calculate the volume/sec entering from the two inlets (Pipes 1 and 2), add them, and then calculate the flow in Pipe 3.
The table illustrates the approach. I calculated the volume of each pipe for a 1 foot section with the indicated diameters, divided by 2 for the radius of each using V = πr²h. Units of V are in^3/foot length. Now we can multiply that volume by the flow rate, in ft/sec, to obtain the flow rate in in^3/sec.
Add the two rates from Pipes 1 and 2 (62.14 in^3/sec) to arrive at the flow rate for Pipe 3 necessary to keep the water level constant. Calculate the volume of 1 foot of Pipe 3 (21.21 in^3/foot) and then divide this into the inflow sum of 62.14 in^3/sec to find the flow rate of Pipe 3 (in feet/sec) necessary to keep the water level constant.
That is 2.93 ft/sec.
Answer:
You need to use option '–author' along with option '-l' to print the author name of each file.
Explanation:
hopefully this helps you sorry if it doesn’t help you
Answer:
a. Use datum on shaft
b. Use datum on hex flat
c. Use datum on face below the head
d. Use datum on shaft
When these datum are used, they will prevent translation and rotation along axis which they act.
Answer:
E = 8.83 kips
Explanation:
First, we determine the stress on the rod:

where,
σ = stress = ?
F = Force Applied = 1300 lb
A = Cross-sectional Area of rod = 0.5
Therefore,

Now, we determine the strain:

Now, the modulus of elasticity (E) is given as:

<u>E = 8.83 kips</u>
Input: what is put in, taken in, or operated on by any process or system.
Output: the amount of something produced by a person, machine, or industry.