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3 years ago

I need help on what’s and input and output to make the flowchart

Engineering

1 answer:

e-lub [12.9K]3 years ago

3 0

Input: what is put in, taken in, or operated on by any process or system.

Output: the amount of something produced by a person, machine, or industry.

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If a law enforcement officer stops a vehicle for a traffic violation and finds a front-seat passenger 18 years of age or older n

Serggg [28]

Safety belt violation would be charged to the front seat passenger.

Answer: Option A.

<u>Explanation:</u>

Essential safety belt laws permit law implementation officials to ticket a driver or traveler for not wearing a safety belt, with no other traffic offense occurring. 11 states incorporate back seats as auxiliary implementation. Five of these are states with essential safety belt laws for front seat tenants.

In 15 of the 50 expresses, the safety belt law is viewed as an optional offense, which implies that a cop can't stop and ticket a driver for the sole offense of not wearing a safety belt. (One special case to this is Colorado, where kids not appropriately limited is an essential offense and brings an a lot bigger fine.)

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3 years ago

Why Elastic Modulus is important and on what it depends?

Bad White [126]

Answer:

The Young's Modulus of a material is a fundamental property of every material that cannot be changed. It is dependent upon temperature and pressure however. The Young's Modulus (or Elastic Modulus) is in essence the stiffness of a material. In other words, it is how easily it is bended or stretched.

Explanation:

Have a great day

5 0

3 years ago

The beam is supported by a pin at A and a roller at B which has negligible weight and a radius of 15 mm. If the coefficient of s

Anettt [7]

Answer:

33.4

Explanation:

Step 1:

\sumMo=0 (moment about the origin)

Fb(15)-Fc(15)=0

Fb=Fc

Step 2:

\sumFx=0

-Fb-Fccos\theta+Ncsin\theta=0

Fc=0.3Nc=Fb

-0.3Nc-0.3Nccos\theta+Ncsin\theta=0

(-0.3-cos\theta+sin\theta)Nc=0----(1)

\sumFy=0

Nccos\theta+Fcsin\theta-Nb=0

Nccos\theta+0.3Ncsin\theta-Nc=0

Nc[cos\theta+0.3sin\theta-1]=0--------(2)

Solving eq (1) and eq (2)

\theta=33.4

Step 3:

As the roller is a two force member

2(90-\phi)+\theta=180

\phi=\theta/2

\phi=Tan(\muN/N)-1

\phi=16.7

\theta=2x16.7=33.4

5 0

3 years ago

Underground water is to be pumped by a 78% efficient 5- kW submerged pump to a pool whose free surface is 30 m above the undergr

maksim [4K]

Answer:

a) The maximum flowrate of the pump is approximately 13,305.22 cm³/s

b) The pressure difference across the pump is approximately 293.118 kPa

Explanation:

The efficiency of the pump = 78%

The power of the pump = 5 -kW

The height of the pool above the underground water, h = 30 m

The diameter of the pipe on the intake side = 7 cm

The diameter of the pipe on the discharge side = 5 cm

a) The maximum flowrate of the pump is given as follows;

$P = \dfrac{Q \cdot \rho \cdot g\cdot h}{\eta_t}$

Where;

P = The power of the pump

Q = The flowrate of the pump

ρ = The density of the fluid = 997 kg/m³

h = The head of the pump = 30 m

g = The acceleration due to gravity ≈ 9.8 m/s²

$\eta_t$ = The efficiency of the pump = 78%

$\therefore Q_{max} = \dfrac{P \cdot \eta_t}{\rho \cdot g\cdot h}$

$Q_{max}$ = 5,000 × 0.78/(997 × 9.8 × 30) ≈ 0.0133 m³/s

The maximum flowrate of the pump $Q_{max}$ ≈ 0.013305 m³/s = 13,305.22 cm³/s

b) The pressure difference across the pump, ΔP = ρ·g·h

∴ ΔP = 997 kg/m³ × 9.8 m/s² × 30 m = 293.118 kPa

The pressure difference across the pump, ΔP ≈ 293.118 kPa

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3 years ago

The figure below appeared three heat treatments processes of steel (A, B and C),

Contact [7]

Answer:

Explanation:

3 0

3 years ago