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1 year ago

Given any two arcs, the larger of the arcs is always called a minor arcTrueFalse

1 answer:

4 0

When we have two arcs in a circle, one larger and one smaller, one will be called the minor arc and the other the minor arc.

The name of the arc depends on its size, for example, given the following green and yellow arcs, the green, which is smaller, will be the minor arc:

Therefore, the larger arc is always called Major arc, not minor arc.

The statement is False.

Answer: False

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21/40 = 52.50% (52.5)

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Answer:

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Step-by-step explanation:

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3 years ago

Hannah claims that people who live in southern states spend 9 hours more per week outside than do people in northern states. She

Aneli [31]

Answer: Hello your question is incomplete below is the missing part

Which of the following statements about Hannah’s claim is supported by the interval?

A) Hannah is likely to be incorrect because the difference in the sample means was 18.6−14.4=4.218.6−14.4=4.2 hours.

B) Hannah is likely to be incorrect because 9 is not contained in the interval.

C)The probability that Hannah is correct is 0.99 because 9 is not contained in the interval.

D)The probability that Hannah is correct is 0.01 because 9 is not contained in the interval.

E)Hannah is likely to be correct because the difference in the sample means (18.6−14.4=4.2)(18.6−14.4=4.2) is contained in the interval.

Answer : Hannah is likely to be incorrect because 9 is not contained in the interval. ( B )

Step-by-step explanation:

The statement that is supported by the interval in Hannah's claim is that

Hannah is likely to be incorrect because 9 is not contained in the interval.

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2 years ago

Solve for 'p'

Darina [25.2K]

$\left(\dfrac{9a^{-4}}{25}\right)^p=\dfrac3{5a^2}$
$\left(\dfrac9{25a^4}\right)^p=\dfrac3{5a^2}$

One way to find $p$ is to notice that the part on the left hand side within the parentheses can be written as a square:

$\dfrac9{25a^4}=\dfrac{3^2}{5^2(a^2)^2}=\left(\dfrac3{5a^2}\right)^2$

So you could write

$\left(\left(\dfrac3{5a^2}\right)^2\right)^p=\left(\dfrac3{5a^2}\right)^{2p}=\dfrac3{5a^2}$

Since these two expressions are equal, and the bases are the same, you know the exponents must be equal, with the exponent on the right hand side being 1. So $2p=1$ , or $p=\dfrac12$ .

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3 years ago