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s344n2d4d5 [400]
2 years ago
15

For each of the following species: C2+ & O2- Write the molecular orbital energy diagram and fill in the electrons Hint: in e

ach case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species. Find the bond order and state whether the species is stable or unstable Hint: Bond order = (# of bonding e- - # of antibonding e-) ¸ 2 Determine if the species is diamagnetic or paramagnetic Hint: indicate the number of unpaired electrons
Chemistry
1 answer:
Tju [1.3M]2 years ago
6 0

Molecular orbital energy is the energy associated with each electron in an atom or molecule.

It is expressed in electron volts (eV) and is determined by the electron's position in the atom or molecule. The molecular orbital energy diagram and fill-in the electrons are given here in each case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species.

C2+: Molecular Orbital Energy Diagram

1s2 2s2 2p2

σ2s*  ← 0 e-  

σ2s   ← 2 e-

σ2p*  ← 0 e-  

σ2p   ← 0 e-

π2p*  ← 0 e-  

π2p   ← 0 e-

Bond Order: 0

Stability: Unstable

Magnetism: Diamagnetic (no unpaired electrons)

O2-: Molecular Orbital Energy Diagram

1s2 2s2 2p4

σ2s*  ← 0 e-  

σ2s   ← 2 e-

σ2p*  ← 0 e-  

σ2p   ← 2 e-

π2p*  ← 0 e-  

π2p   ← 2 e-

Bond Order: 1

Stability: Stable

Magnetism: Paramagnetic (2 unpaired electrons)

For more questions like Molecular orbital theory click the link below:

brainly.com/question/20436223

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Answer:

A. a magnet

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3 0
3 years ago
Two moles of an ideal gas are placed in a container whose volume is 2.3 x 10^-3 m3. The absolute pressure of the gas is 6.9 x 10
PtichkaEL [24]

Answer:

K.E.=1.97\times 10^{-21}\ J

Explanation:

Given that:-

Pressure = 6.9\times 10^5\ Pa

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = \frac {1}{101325} P (atm)

Given the value of pressure = 43,836 Pa

So,  

6.9\times 10^5\ Pa = \frac{6.9\times 10^5}{101325} atm

Pressure = 6.80977 atm

Volume = 2.3\times 10^{-3}\ m^3 = 2.3 L ( 1 m³ = 1000 L)

n = 2 mol

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

6.80977 atm × 2.3 L = 2 mol × 0.0821 L.atm/K.mol × T

⇒T = 95.39 K

The expression for the kinetic energy is:-

K.E.=\frac{3}{2}\times K\times T

k is Boltzmann's constant = 1.38\times 10^{-23}\ J/K

T is the temperature

So, K.E.=\frac{3}{2}\times 1.38\times 10^{-23}\times 95.39\ J

K.E.=1.97\times 10^{-21}\ J

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