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Elan Coil [88]
3 years ago
10

Calculate the enthalpy change for the reaction Mn3O4(s)+CO(g)⟶3MnO(s)+CO2(g) from the following:

Chemistry
1 answer:
faust18 [17]3 years ago
3 0

Answer:

- 50.7 kJ.

Explanation:

  • To get the enthalpy change for the reaction:

Mn₃O₄(s) + CO(g) ⟶ 3MnO(s) + CO₂(g).

  • We must orient the given reactions in a way that its sum give the required reaction.

The first reaction be as it is:

Mn₃O₄(s) + 4CO(g) ⟶ 3Mn(s) + 4CO₂(g), <em>ΔH₁ = 255.6 kJ.</em>

The second reaction should be reversed and multiplied by 3 and also the value of its ΔH must multiplied by (- 3):

3Mn(s) + 3CO₂(g) ⟶ 3MnO(s) + 3CO(g), <em>ΔH₂ = (- 3)(102.1 kJ) = - 306.3 kJ.</em>

  • By summing the two reactions after the modification, we get the required reaction:

<em>Mn₃O₄(s) + CO(g) ⟶ 3MnO(s) + CO₂(g).</em>

<em></em>

<em>∴ ΔH rxn = ΔH₁ + ΔH₂ = (255.6 kJ) + (- 306.3 kJ) = - 50.7 kJ.</em>

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Define: 1. acids, 2. strong acids, 3. weak acids.
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Answer:

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Perform the following operationand express the answer inscientific notation.7.00x10^5 - 5.00x10^4
11Alexandr11 [23.1K]

Taking into account the scientific notation,  the result of the subtraction is 6.5×10⁵.

<h3>Scientific notation</h3>

First, remember that scientific notation is a quick way to represent a number using powers of base ten.

The numbers are written as a product:

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<h3 /><h3>Subtraction in scientific notation</h3>

You want to subtract two numbers in scientific notation. It should be noted that when the numbers to be added do not have the same base 10 exponent, the base 10 power with the highest exponent must be found. In this case, the highest exponent is 5.

Then all the values ​​are expressed as a function of the base 10 exponent with the highest exponent. In this case: 5.00×10⁴=0.500×10⁵

Taking the quantities to the same exponent, all you have to do is subtract what was previously called the number "a". In this case:

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3 0
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How many moles of chromium III nitrate are produced When chromium reacts with 0.85 moles of lead for nitrate to produce chromium
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0.85 moles formula units of lead nitrate will produce 0.57 moles formula units of chromium (III) nitrate.

<h3>Explanation</h3>

Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as \text{Pb}^{2+} ions. The formula for a nitrate ion is {\text{NO}_3}^{-}. The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each \text{Pb}^{2+} ion in lead nitrate would pair up with two {\text{NO}_3}^{-} ions. The formula for lead nitrate will be \text{Pb}({\text{NO}_3})_2. Each formula unit of lead nitrate will contain one \text{Pb}^{2+} ion and two {\text{NO}_3}^{-} ions.

The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as \text{Cr}^{3+}. Similarly, each \text{Cr}^{3+} will pair up with three {\text{NO}_3}^{-} ions. The formula for chromium (III) nitrate will be \text{Cr}(\text{NO}_3})_3. Each formula unit of chromium (III) nitrate will contain one {\text{NO}_3}^{-} ion and three {\text{NO}_3}^{-} ions.

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