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Tamiku [17]
3 years ago
9

A primary purpose of conducting a hazardous materials exercise is to find out:

Chemistry
1 answer:
SVEN [57.7K]3 years ago
3 0
The hazardous materials tabletop exercises are to provide an opportunity for communities to test their abilities to respond incidents caused by to hazardous materials. From these exercises, the management identifies the issues and resolution to the incidents. Answer here is <span>. whether planned procedures work</span>
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Draw the curved arrow mechanism for the addition of HCN in water with NaOH to 3,4-dimethylcyclopentan-1-one to give the correspo
Crank

Answer:

See picture and explanation below

Explanation:

In the attached picture you have the answer for this.

In the first step, we have an acid base reaction between HCN and NaOH. When this happens, its formed the following:

HCN + NaOH --------> CN⁻ + H₂O + Na⁺

As a second step, The CN⁻ attacks the carbonile group in the cyclopentane. This causes to open the double bond, and then, the Cyano enters the molecule.

The final step is another acid base reaction, where the oxygen substracts a hydrogen atom of the water in the medium, and then, the alcohol group is formed. With this step, the cyanohydrin is finally formed. See the mechanism below in the picture.

Hope this helps

6 0
3 years ago
How make carbon dioxide ​
puteri [66]

Answer:

Carbon dioxide is produced whenever an acid reacts with a carbonate. This makes carbon dioxide easy to make in the laboratory. Calcium carbonate and hydrochloric acid are usually used because they are cheap and easy to obtain. Carbon dioxide can be collected over water, as shown in the diagram.

6 0
3 years ago
How many significant figures does 104,000 have
JulijaS [17]

Answer:

104,000 has 3 significant figure.

Explanation:

This is because all non-zero digits are significant and zeros in between non-zero digits are significant.

7 0
3 years ago
If you push a crate with 50N of force for 10 meters in 5 seconds how much power dis u use​
morpeh [17]

Answer:

Hi... Your answer is 10*50=500

5 0
2 years ago
Read 2 more answers
PLEASE HELP- I WILL GIVE BRAINLIEST AND THANKS
julsineya [31]

Answer:

The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams

Explanation:

The question is with regards to density calculations

The density of the given sodium carbonate solution, ρ = 0.4 g/dm³

The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³

Density \ of \ an \ object, \rho  = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }

\rho = \dfrac{m}{V}

Therefore, we have;

The \ Density \ of \ the \ sodium \ carbonate, \ \rho  = 0.4 \ g/dm^3 =  \dfrac{m }{ 0.01 \ dm^3 }

The mass, "m", of the sodium carbonate in  = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g

The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.

8 0
3 years ago
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