Answer:
1 2 3 4 5 6 7 8 9 10.... etc
Step-by-step explanation:
What number goes between the numbers that I put.
The diagonals are:
diagonal₁=2x+3y
diagonal₂=(x+8)+(2y+5)
We have to solve the following system of equations:
2x=3y
(x+8)=(2y+5)
We solve this system by substitution method:
2x=3y ⇒x=3y/2
(3y/2 +8)=2y+5
3y+16=4y+10
-y=-6
y=6
x=3y/2=3*6/2=9
we obtain the measure of the diagonals:
diagonal₁=2x+3y=2*9+3*6=18+18=36
diagonal₂=(x+8)+(2y+5)=(9+8)+(2*6+5)=17+17=34
Answer: The longest diagonal is 36 units.
Answer:
erm....
Step-by-step explanation:
you are gonna have to give us a little bit more of the background info here!
Heyo!
Solve the equation
1/3(2x -4) + 5 = -2/3(x +1)
Distribute 1/3 through the parenthesis
2/3x -4/3 + 5 = -2/3(x +1)
Distribute -2/3 through the parenthesis
2/3x -4/3 + 5 = -2/3x - 2/3
Calculate the sum or difference
2/3x + 11/3 = -2/3x -2/3
Multiply both sides of the equation by 3
2x + 11 = -2x -2
Move variable to the left side and change its sign
2x + 2x + 11 = -2
Move constant to the right side and change its sign
2x + 2x = -2 -11
Collect the like terms
4x = -2 -11
Calculate the sum or difference
4x = -13
Divide both sides of the equation by 4
x = -13/4
