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Cloud [144]
1 year ago
14

Funds are distributed to five families affected by floods in the ratio 5:12:2:15:29. The total amount that the five families rec

eived was $630.
a) The first family received _____
b) The difference between the amount of money the first and last family received was _____
c) A sixth family joins. They receive n amount of money and the average amount of money donated to all six families becomes 140. How much money does the sixth family receive?
Mathematics
1 answer:
serious [3.7K]1 year ago
8 0

Step-by-step explanation:

  • We must first add up the ratios:5+12+2+15+29 = 63, this will be the total ratio the money was shared
  • Then we pick out the ratio for each family accordingly:

For the first family, 5 out of the total ratio = 5/63

For the second family, 12 out of the total ratio = 12/63

For the third family, 2 out of the total ratio = 15/63

For the fifth family, 29 out of the total ratio = 29/63

a) The first family = 5/63 of the money, $630

we can therefore say the money they received is

= 5/63 ×630

= $50

b) The last family = fifth family = 29/63 of the money, 630

= 29/63 × 630

= $290

recall that the first family received $50 , the positive difference between the money received by both the first and last family

= $290 - $50

= $240

c) Since another family joins in, the total number of families become 6

  • the money the received is n

we can't find the average without knowing what the second, third, and fourth family received out of that money

  • we apply the same step

the second family = 12/63 ×630

= $120

the third family = 2/63 × 630

= $20

the fourth family = 15/63 × 630

= $150

  • Average generally is = total sum/ frequency or number of occurrences or people

in this case, we were told the average became $140

which means that

sum of money received by the families/ the number of families involved in the sharing = $140

<h3> ( $50+$120+$20+$150+$290+n)/6 = $140</h3>

($630+n)/6= $140

now the plan would be to make n subject of formula

  • multiply both sides of the equation by 6, the equation will become

$630+n = $840

take $630 to the other side, it becomes -$630

n = $840-$630

n = $210

therefore the newly added family received $210

I honestly hope I explained it properly...thank you

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Answer:

The series is 5 , 6 , 7 , 8 , 9 , 10 , 11

Step-by-step explanation:

* Lets revise the arithmetic series

- In the arithmetic series there is a constant difference between

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- Ex:

# 2  ,  5  ,  8  ,  11  ,  ……………………….  (constant difference is 3)

# 5  ,  10  ,  15  ,  20  ,  …………………………  (constant difference is 5)

# 12  ,  10  ,  8  ,  6  ,  ……………………………  (constant difference is -2)

* General term (nth term) of an Arithmetic series:

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* Lets solve the problem

- Jeff wants to increase the number of miles he runs each day

∴ He will add the initial value by constant number each day

- He plans on increasing the number of miles he runs a day by 1

∴ The constant value is 1 mile

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- He do that for the remainder of the week

∵ The week has 7 days

∴ The series has 7 terms

∵ The rule of the series is Un = a + (n - 1)d

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∴ Un = 5 + (n - 1)(1)

∴ Un = 5 + n - 1

∴ Un = 4 + n ⇒ n is the position of the number

- Substitute n from 1 to 7 to find the series

∴ The series is 5 , 6 , 7 , 8 , 9 , 10 , 11

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