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In-s [12.5K]
3 years ago
13

Which number is an irrational number?

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
6 0

Answer:

3.5

Step-by-step explanation:

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Solve using number line (-10)+6<br> ​
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Answer:

       

Step-by-step explanation:

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2 years ago
Which of the following values of d will result in a true statement when substituted into the given equation?
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I think it's D cause the parentheses always comes first so 2-d)=2 hope that helps
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In Lily's garden, there are 5 rose bushes the first year. Each year, she adds two new rose bushes. She
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Step-by-step explanation:

Let x = the number of years since the first year and let y = the total number of plants.

Roses: y = 5 + 2x

Tulips: y = 20 – 3x

You can use elimination to solve.

y = 5 + 2x

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0 = -15 + 5x

15 = 5x

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This means that 3 years after the first year, the number of rose bushes equals the number of tulip plants.

The graphs appear to

intersect at (3, 11) which verifies that x=3

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2 years ago
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How many days is in:<br><br>3 weeks<br>5 weeks<br>7 weeks<br>9 weeks​
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Answer:

3 weeks 21 days, 5 weeks 35, 7 weeks 49, 9 weeks 63 days

Step-by-step explanation:

Each week is 7 days

8 0
2 years ago
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The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units
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Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&A&(~ 2 &,& 8~) &#10;%  (c,d)&#10;&C&(~ 6 &,& 2~)&#10;\end{array}~~~ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}&#10;\\\\\\&#10;AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}&#10;\\\\\\&#10;AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&A&(~ 2 &,& 8~) &#10;%  (c,d)&#10;&B&(~ 16 &,& 2~)&#10;\end{array}\\\\\\&#10;AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}&#10;\\\\\\&#10;AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}&#10;\\\\\\&#10;AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0
3 years ago
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