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IgorLugansk [536]
3 years ago
12

Bob's monthly bill is made up of a $10 fee plus $0.05 per minute. Write an expression that represents Bob's monthly phone if he

talks for m minute.If Bob talks for 350 minutes,how much will his phone bill be?​
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Answer:

10 + 0.05m; m = 350 minutes

Bob's phone bill will be $27.50

Step-by-step explanation:

$10 + ($0.05 x 350 minutes) = $27.50

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3 years ago
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
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The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

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1 year ago
Each month at Sea Stars, the
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Answer:

A good rule is to change 10 to 15 percent of the water each week. If your tank is heavily stocked, bump that up to 20 percent each week. A lightly stocked aquarium can maybe get by for two to four weeks, but this should be the maximum length of time between water changes.

Step-by-step explanation:

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Answer:

no they don't

Step-by-step explanation:

leah has a higher goal-assist ratio with 1 more assist than maddie

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A + b = dr, solve for a
AURORKA [14]

Hey there!

Since we don't have values for b, d, and r, we can't get a specific number for the value of a, if that makes sense. It'll be represented by these variables.

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