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sineoko [7]
1 year ago
10

Determine if the lim f(x) exists using the graph below.. If it does, find its value. If it does not,x 1explain why

Mathematics
1 answer:
Leno4ka [110]1 year ago
8 0

The limit of a function f at a point a exists if:

\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)\begin{gathered} \text{ From the given image, the value of the left limit of f at x=1 } \\ \lim_{x\to a^-}f(x)\lt1 \end{gathered}

Also,

\begin{gathered} \text{ From the given image, the value of the right limit of f at x=1 } \\ \lim_{x\to a^+}f(x)\gt1 \end{gathered}

Therefore,

\lim_{x\to1^-}f(x)\lim_{x\to1^+}f(x)

Hence, the limit does not exist

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Plz help due tonight
MariettaO [177]

Sum of the interior angles of any triangle equal to 180 degrees thus :

60 + 70 + 8x + 2 = 180

8x + 132 = 180

Subtract both sides 132

8x + 132 - 132 = 180 - 132

8x = 48

Divide both sides by 8

8x ÷ 8 = 48 ÷ 8

<h2>x = 6 </h2>

6 0
3 years ago
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I need help with #10.
abruzzese [7]

Answer:

#10=10

Step-by-step explanation:

5 0
3 years ago
A certain compound has a half-life of four days. Write and use an exponential decay function to find the amount of compound rema
dimaraw [331]

Answer:

1.97 ounces

Step-by-step explanation:

-The exponential decay function is given by the formula:

P_t=P_oe^{-rt}\\\\

Given that the half-life is 4 days, we can substitute in the formula to solve the rate of decay for a single half-life:

P_t=P_oe^{rt}\\\\P_t=0.5P_o\\\\\therefore 0.5=e^{-4r}\\\\-4r=In(0.5)\\\\r=0.17329

#Since, 1 week has 7 days, 3 weeks is a 21-day period, thus, t=21.

#We substitute and solve for the amount remaining after 21days of decay:

P_t=P_oe^{-rt}\\\\=75e^{-21\times 0.17329}\\\\=1.97072\\\\\approx1.97 \ oz

Hence, the amount remaining after 3 weeks of decays is approximately 1.97 ounces

4 0
3 years ago
PLEASE HELP WITH THIS QUESTION
Burka [1]
One nice thing about this situation is that you’ve been given everything in the same base. To review a little on the laws of exponents, when you have two exponents with the same base being:

– Multiplied: Add their exponents
– Divided: Subtract their exponents

We can see that in both the numerator and denominator we have exponents *multiplied* together, and the product in the numerator is being *divided* by the product in the detonator, so that translates to *summing the exponents on the top and bottom and then finding their difference*. Let’s throw away the twos for a moment and just focus on the exponents. We have

[11/2 + (-7) + (-5)] - [3 + 1/2 + (-10)]

For convenience’s sake, I’m going to turn 11/2 into the mixed number 5 1/2. Summing the terms in the first brackets gives us

5 1/2 + (-7) + (-5) = - 1 1/2 + (-5) = -6 1/2

And summing the terms in the second:

3 + 1/2 + (-10) = 3 1/2 + (-10) = -6 1/2

Putting those both into our first question gives us -6 1/2 - (-6 1/2), which is 0, since any number minus itself gives us 0.

Now we can bring the 2 back into the mix. The 0 we found is the exponent the 2 is being raised to, so our answer is

2^0, which is just 1.
5 0
4 years ago
Which of the following statements are true of the discriminant? The discriminant is b2 – 4ac in the quadratic formula. The discr
steposvetlana [31]
A is true If im not mistaking 
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3 years ago
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