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sineoko [7]
1 year ago
10

Determine if the lim f(x) exists using the graph below.. If it does, find its value. If it does not,x 1explain why

Mathematics
1 answer:
Leno4ka [110]1 year ago
8 0

The limit of a function f at a point a exists if:

\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)\begin{gathered} \text{ From the given image, the value of the left limit of f at x=1 } \\ \lim_{x\to a^-}f(x)\lt1 \end{gathered}

Also,

\begin{gathered} \text{ From the given image, the value of the right limit of f at x=1 } \\ \lim_{x\to a^+}f(x)\gt1 \end{gathered}

Therefore,

\lim_{x\to1^-}f(x)\lim_{x\to1^+}f(x)

Hence, the limit does not exist

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8. You recorded the time in seconds it took for 8 participants to solve a puzzle. The times were: 15.2, 18.8, 19.3, 19.7, 20.2,
kirill115 [55]

Answer:

Xbar = 20.813

Median = 19.95

5 - number summary :

Minimum = 15.2

Q1 = 19.05; Q2 = 19.95 ; Q3 = 21.95 ; maximum = 29.4

Standard deviation, s = 4.068

Step-by-step explanation:

Given the data:

X : 15.2, 18.8, 19.3, 19.7, 20.2, 21.8, 22.1, 29.4

Ordered data:

15.2, 18.8, 19.3, 19.7, 20.2, 21.8, 22.1, 29.4

The mean (xbar) :

Xbar = Σx / n ; n = sample size = 8

Xbar = 166.8 / 8 = 20.8125

Xbar = 20.813

The median :

1/2 *(n+1)th term

1/2(9) = 4.5

(4 + 5)th term / 2

(19.7 + 20.2) / 2 = 19.95

The five number summary :

Minimum = 15.2

Lower quartile (Q1) = 1/4(9) = 2.25 ; (2nd + 3rd) term / 2

(18.8 + 19.3) / 2 = 19.05

Median (Q2) = 19.95

Upper quartile (Q3) :

3/4(9) = 6.75 = (6th + 7th) / 2

(21.8 + 22.1) / 2 = 21.95

Maximum = 29.4

The standard deviation, s = sqrt[(x - xbar)²/ (n-1)]

Using calculator ;

s = 4.068

4 0
3 years ago
Hello please help i’ll give brainliest
morpeh [17]

Answer:

Purpose!!

Step-by-step explanation:

These are examples of an author's purpose of writing something! :)

5 0
3 years ago
Read 2 more answers
8 cm<br> 5 cm<br> 10 cm<br> 12 cm
lana66690 [7]

Answer:

35 cm

Step-by-step explanation:

6 0
3 years ago
Ace Cars says they will pay Jim a 10% commission on the sale price of each car. Budget Cars says they will pay him $500 per week
Arisa [49]

Answer:

  $20,000

Step-by-step explanation:

You can quickly figure this by recognizing that the difference in commission must be the same as the base salary:

  2.5%(car price) = $500

  car price = $500/0.025 = $20,000

__

If you prefer, you can get there with equations.

At Job 1, the pay is ...

  y = 10%×(car price)

At Job 2, the pay is ...

  y = 7.5%×(car price)

Setting the equal (the two opportunities pay the same), we have ...

  0.10(car price) = 500 +0.075(car price)

  0.025(car price) = 500 . . . . . . . . subtract 0.075(car price)

  car price = 500/0.025 = 20,000 . . . . divide by 0.025

Jim would have to sell a $20,000 car each week for the jobs to pay the same.

8 0
3 years ago
Pls help i need help :D
docker41 [41]

Answer:

\frac{2808}{3125}

Step-by-step explanation:

8 0
3 years ago
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