Triangle LMN with vertices L(-9,-1) M(-3,-4) and N(-5,-8)
1 answer:
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Set the width to be x. Thus, the length is 4x.
The perimeter is 2(x+4x)=100, so x=10.
Plugging in x=10, you get that 4x=40.
So, the area of the rectangle is 400 .
Because there are 100 centimeters in a meter and you are asking for area, you must multiply by to get 4000000
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The complete question in the attached figure
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°