set them equal to each other
x²+1=x+1
minus 1 from both sides
x²=x
minus x both sides
x²-x=0
factor
x(x-1)=0
set each to 0
x=0
x-1=0
x=1
subsitute back to find y values
y=x+1, y=0+1, y=1, one point is (0,1)
y=x+1, y=1+1, y=2, another point is (1,2)
the 2 points of intersection are (0,1) and (1,2)
<span>The general equation of a quadratic is expressed as y = ax^2+bx+c. To
convert the general equation to vertex form, we need to obtain this form:
(y- k)= a(x - h)^2
This could be done by using completing the square method.
</span><span>y = –3x^2 – 12x – 2
</span><span>y + 2 = –3(x^2 + 4x)
</span>y + 2 -12 <span>= –3(x^2 + 4x + 4)
</span>y - 10 = -3(x+2)^2
Therefore, the answer is the first option.
your answer is B i hope this helpss
Answer:
i got u
Step-by-step explanation:
i got u
Assuming 5 is the base. I'm going to leave that out for now.
2log(5x^3) + (1/3)log(x^2+6)
power rule
log(5^2 x^3*2) + log((x^2 + 6)^(1/3))
log(25x^6) + log((x^2 + 6)^(1/3))
quotient rule
log(25x^6 / (x^2 + 6)^(1/3))