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1 year ago

What is a similar rectangle?

Mathematics

1 answer:

amid [387]1 year ago

3 0

<h3>What are similar shapes?</h3>

When applying a scale factor, similar shapes are enlarged versions of one another. All of the matching angles and lengths in related shapes are equal and in the same ratio.

Rectangle is also a kind of shape. So, defining similar rectangle two rectangles must have proportional sides in order for them to be identical (form equal ratios) i.e., ratio of the two longer sides should equal the ratio of the two shorter sides.

Steps to find similar rectangle in math:

Choose the pairs of corresponding sides on each side.
Determine the sides' ratios.
Verify that the ratios are identical.

To know more about similar rectangles, follow link:

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Suppose you are given information about a triangle according to SSS, SAS, and ASA. For which of these can you immediately use th

jek_recluse [69]

Answer:

SSS and SAS

Step-by-step explanation:

Law of cosines: The law of cosines is used for calculating one side of a triangle when the angle opposite and the other two sides are known.

If the information about a triangle according to SSS, SAS and ASA is given, then we will immediately use SSS and SAS by using the law of cosines to find one of the remaining measures because Law of cosines is applied if we know one angle opposite and the other two sides.

Also, in ASA, we know two angles and one side, thus we cannot use Law of cosines in this, rather Law of sines can be accurately use in this case.

if you have two sides, encroaching an angle, then the Law of Cosines can be used to find a missing side, thus SAS will work fine for that, now, if you have no angles given, but you know all sides, you can use the Law of Cosines as well, by solving it for the angle, and get the angles, on which case, SSS will do... .now as far as ASA, if you have two angles and one side known, then... that's not very workable for the law of cosines

please mark me brainliest :)

3 0

3 years ago

Read 2 more answers

DIC A student has a total of $3000 in student loans that will be paid with a 48-month installment loan with monthly payments of

gtnhenbr [62]

Answer:

The APR of the loan was 18.30%.

Step-by-step explanation:

Given that a student has a total of $ 3000 in student loans that will be paid with a 48-month installment loan with monthly payments of $ 73.94, to determine the APR of the loan to the nearest one-half of a percent the following calculation must be done:

3,000 = 100

(73.94 x 48) = X

3,000 = 100

3,549.12 = X

3,549.12 x 100 / 3,000 = X

354,912 / 3000 = X

118.30 = X

118.30 - 100 = 18.30

Therefore, the APR of the loan was 18.30%.

5 0

3 years ago

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

3 years ago

Arrange the following numbers in order from least to greatest.<br><br>7, 7.1, 7.2, √51<br>

never [62]

Answer:

7, 7.1, √51, 7.2

Step-by-step explanation:

√51 is 7.14

5 0

3 years ago

The clock below shows time that lance got home from school. 3:32. What time did he get home A: seventeen minutes before three B:

navik [9.2K]

Answer:

If Lance got home from school at 3:32 p.m. A and B both represent:

A: seventeen minutes before 3 would be before 3 o'clock even happens

B: 28 minutes before 4 would make more sense, since 3:32 is before 4 o'clock

Lance got home 28 minutes before 4

Hope this helps ;)

5 0

3 years ago