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Sidana [21]
3 years ago
13

The width of a rectangle is 3 units less than the length. The area of the rectangle is 28 units. What is the width, in units, of

the rectangle.
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
8 0

Answer:

4

Step-by-step explanation:

Let's call the width W and the length L.

We know the width is 3 less than the length, so:

W = L - 3

And we know the area is 28, so:

28 = WL

If we solve for L in the first equation:

L = W + 3

And substitute into the second equation:

28 = W (W + 3)

28 = W² + 3W

0 = W² + 3W - 28

0 = (W + 7) (W - 4)

W = -7, 4

Since W can't be negative, W = 4 units.

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I believe it is x = 2f

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3 years ago
The curved part of this figure is a semicircle. What is the best approximation for the area of this figure? 18+12.125π units² 36
andreyandreev [35.5K]

Answer:

18+12.125π units²

Step-by-step explanation:

The diameter of the semicircle can be found by the use Pythagoras theorem.

Δx²+Δy²=d²

Δx=3--1=4

Δy=3--6=9

d²=4²+9²

d=√(16+81)

Area=πr²/2

=π×(√(16+81)/2)²÷2

=[π×(97)/4]/2

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=18+12.125π units²

97π/8 is equivalent to 18+12.125π units²

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3 years ago
Dario purchased a 1-foot long piece of gum, and he decides to share it with 3 of his friends. So, he cuts the piece of gum into
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Answer:

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4 0
3 years ago
The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5
vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score,\bar x=3.5

Score(x)   frequency   C.F

1                  1                 1

2                  3                4

3                  f                 15(4+f=4+11)

4                  13               28

5                   4               32

\sum f_i=1+3+f+13+4=21+f

\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f

(\bar x)=\frac{\sum f_ix_i}{\sum f_i}

Using the formula

3.5=\frac{79+3f}{21+f}

73.5+3.5f=79+3f

3.5f-3f=79-73.5

0.5f=5.5

f=\frac{5.5}{0.5}=11

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}

Median=\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4

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