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Tcecarenko [31]
3 years ago
6

A rectangular prism has a height of 12 cm and a square base with sides measuring 5 cm. A pyramid with the same base and the heig

ht of the prism is placed inside the prism. What is the volume of the space outside the pyramid but inside the prism?
Mathematics
1 answer:
Ksju [112]3 years ago
3 0
The answer is 200 cm³


The volume of the rectangular prism (V1) is:
V1 = l · w · h                       (l - length,  w - width,  h - height)
It is given:
h = 12 cm
w = l = 5 cm (since it has a square base which all sides are the same size).
Thus: V1 = 12 · 5 · 5 = 300 cm³

The volume of pyramid (V2) is:
V2 = 1/3 · l · w · h                   (l - length,  w - width,  h - height)
It is given:
h = 12 cm
w = l = 5 cm (since it has a square base which all sides are the same size).
V2 = 1/3 · 12 · 5 · 5 = 1/3 · 300 = 100 cm³


The volume of the space outside the pyramid but inside the prism (V) is a difference between the volume of the rectangular prism (V1) and the volume of the pyramid (V2): 
V = V1 - V2 = 300 cm³ - 100 cm³ = 200 cm³
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b

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Step-by-step explanation:

From the question we are told that

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   The number of student that will cheat is  k =  3

   The number of students that he is focused on is  n  =  4

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Generally  probability mass function is mathematically represented as

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Here C stands for combination , hence we will be making use of the combination functionality in our calculators  

Generally the that  he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

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   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{17} C_{4}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ 1 *  2380}{ 4845}

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